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Match the justification for each step. on S. CE- CD + DE 6-8+ (3x+ 7) 6x-15 + 3x 3x-15 x-5

Match the justification for each step. on S. CE- CD + DE 6-8+ (3x+ 7) 6x-15 + 3x 3x-15 x-5

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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New windOW 6. MPOR-MPOS + MSOR New incognito wi 90-2x + (4x-12) 90-6x - 12 History x9- 201 Downloads Bookmarks m.POR - MLPOS+ MSOR Zoom uan9 Print. O Addition Prop. = IZI - x) +x2 - 06 Cast. pul 90- 6x - 12 More tools O Substitution Edit 102 = 6x Simplify Settings Help 9 Division prop. = Identify the property that justifies the statement.
Transcribed Image Text:New windOW 6. MPOR-MPOS + MSOR New incognito wi 90-2x + (4x-12) 90-6x - 12 History x9- 201 Downloads Bookmarks m.POR - MLPOS+ MSOR Zoom uan9 Print. O Addition Prop. = IZI - x) +x2 - 06 Cast. pul 90- 6x - 12 More tools O Substitution Edit 102 = 6x Simplify Settings Help 9 Division prop. = Identify the property that justifies the statement.
Your justification is "sımplity". 1 Match the justification for each step. 5. CE - CD + DE 6x=8+ (3x + 7) 6x-15+3x 3x 15 x-5 Given CE - CD + DE O Subtraction prop. of = 6x-8+ (3x + 7) O Substitution 6x- 15 + 3x O Division Properti of = 3x = 15 Simplify X = 5 Match the justiication for each step.
Transcribed Image Text:Your justification is "sımplity". 1 Match the justification for each step. 5. CE - CD + DE 6x=8+ (3x + 7) 6x-15+3x 3x 15 x-5 Given CE - CD + DE O Subtraction prop. of = 6x-8+ (3x + 7) O Substitution 6x- 15 + 3x O Division Properti of = 3x = 15 Simplify X = 5 Match the justiication for each step.
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