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Match the following aqueous solutions with the appropriate letter from the column on the right. O 1. 0.12 m CaBr2 A. Highest boiling point | 2. 0.20 m NH¼CH,C0O 3. 0.17 m NANO3 4. 0.31 m Glucose(nonelectrolyte) B. Second highest boiling point C. Third highest boiling point D. Lowest boiling point

Match the following aqueous solutions with the appropriate letter from the column on the right. O 1. 0.12 m CaBr2 A. Highest boiling point | 2. 0.20 m NH¼CH,C0O 3. 0.17 m NANO3 4. 0.31 m Glucose(nonelectrolyte) B. Second highest boiling point C. Third highest boiling point D. Lowest boiling point

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Match the following aqueous solutions with the appropriate letter from the column on the right.

Match the following aqueous solutions with the appropriate letter from the column on the right. 1. 0.12 m CaBr2 A. Highest boiling point | 2. 0.20 m NH¼CH3COO B. Second highest boiling point C. Third highest boiling point 4. 0.31 m Glucose(nonelectrolyte) D. Lowest boiling point 3. 0.17 m NANO3 Submit Answer Retry Entire Group 9 more group attempts remaining
Transcribed Image Text:Match the following aqueous solutions with the appropriate letter from the column on the right. 1. 0.12 m CaBr2 A. Highest boiling point | 2. 0.20 m NH¼CH3COO B. Second highest boiling point C. Third highest boiling point 4. 0.31 m Glucose(nonelectrolyte) D. Lowest boiling point 3. 0.17 m NANO3 Submit Answer Retry Entire Group 9 more group attempts remaining
Expert Solution
Step 1

The elevation in boiling point is given by -

∆Tb = i × kb × m

T2 - T1 = i × kb × m

where 

  • kb = boiling point elevation constant = 0.512oC/m
  • i = van't Hoff factor 
  • m = molality of solution
  • T2 = boiling point of solution 
  • T1 = boiling point of pure solvent

Now, 

∆Tb is directly proportional to i x m . Higher the value of i x m , higher will be the boiling point of solution and vice-versa.

 

 

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