Match the following aqueous solutions with the appropriate letter from the column on the right. 1. 0.18 m Ni(NO3)2 A. Lowest freezing point 2. 0.25 m ZNSO4 B. Second lowest freezing point 3. 0.20 m CoCl2 C. Third lowest freezing point 4. 0.56 m Sucrose(nonelectrolyte) D. Highest freezing point

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**Freezing Point Depression Activity**

Match the following aqueous solutions with the appropriate letter from the column on the right.

**Solutions:**
1. 0.18 m Ni(NO₃)₂
2. 0.25 m ZnSO₄
3. 0.20 m CoCl₂
4. 0.56 m Sucrose (nonelectrolyte)

**Categories:**
A. Lowest freezing point
B. Second lowest freezing point
C. Third lowest freezing point
D. Highest freezing point

---

**Explanation:**

Freezing point depression depends on the molality of the solution and the number of particles the compound dissociates into when dissolved in water. Electrolytes, which dissociate into ions, will cause a greater freezing point depression than nonelectrolytes at the same molality.

- **Ni(NO₃)₂** dissociates into 3 ions (Ni²⁺ and 2 NO₃⁻).
- **ZnSO₄** dissociates into 2 ions (Zn²⁺ and SO₄²⁻).
- **CoCl₂** dissociates into 3 ions (Co²⁺ and 2 Cl⁻).
- **Sucrose** does not dissociate, so it remains 1 molecule in solution.

Using the van 't Hoff factor (i), which represents the number of particles into which a solute dissociates, we can predict:

1. 0.18 m Ni(NO₃)₂ (i = 3)
2. 0.25 m ZnSO₄ (i = 2)
3. 0.20 m CoCl₂ (i = 3)
4. 0.56 m Sucrose (i = 1)

Multiplying molality by the van 't Hoff factor:

- **0.18 m Ni(NO₃)₂** : 0.18 * 3 = 0.54
- **0.25 m ZnSO₄** : 0.25 * 2 = 0.50
- **0.20 m CoCl₂** : 0.20 * 3 = 0.60
- **0.56 m Sucrose (nonelectrolyte)** : 0.56 * 1 = 0.56

Thus, the solutions in order from lowest to highest freezing
Transcribed Image Text:**Freezing Point Depression Activity** Match the following aqueous solutions with the appropriate letter from the column on the right. **Solutions:** 1. 0.18 m Ni(NO₃)₂ 2. 0.25 m ZnSO₄ 3. 0.20 m CoCl₂ 4. 0.56 m Sucrose (nonelectrolyte) **Categories:** A. Lowest freezing point B. Second lowest freezing point C. Third lowest freezing point D. Highest freezing point --- **Explanation:** Freezing point depression depends on the molality of the solution and the number of particles the compound dissociates into when dissolved in water. Electrolytes, which dissociate into ions, will cause a greater freezing point depression than nonelectrolytes at the same molality. - **Ni(NO₃)₂** dissociates into 3 ions (Ni²⁺ and 2 NO₃⁻). - **ZnSO₄** dissociates into 2 ions (Zn²⁺ and SO₄²⁻). - **CoCl₂** dissociates into 3 ions (Co²⁺ and 2 Cl⁻). - **Sucrose** does not dissociate, so it remains 1 molecule in solution. Using the van 't Hoff factor (i), which represents the number of particles into which a solute dissociates, we can predict: 1. 0.18 m Ni(NO₃)₂ (i = 3) 2. 0.25 m ZnSO₄ (i = 2) 3. 0.20 m CoCl₂ (i = 3) 4. 0.56 m Sucrose (i = 1) Multiplying molality by the van 't Hoff factor: - **0.18 m Ni(NO₃)₂** : 0.18 * 3 = 0.54 - **0.25 m ZnSO₄** : 0.25 * 2 = 0.50 - **0.20 m CoCl₂** : 0.20 * 3 = 0.60 - **0.56 m Sucrose (nonelectrolyte)** : 0.56 * 1 = 0.56 Thus, the solutions in order from lowest to highest freezing
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