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Match each initial value problem with the corresponding interval of existence and uniqueness 1 In(1+x) -y+ tanx, y(¹/3)=-1 1 In(1+x) 1 (1-x²) 1 (1-x²) y' = y' + y' + -y+ tanx, y(-/4)=2 -y= tanx, y(1/3) = -1 -y= tanx, y(-/4) = 2 A. (-1,0) π 2 B.(1, (⁰.1) D. (-1,1)

Match each initial value problem with the corresponding interval of existence and uniqueness 1 In(1+x) -y+ tanx, y(¹/3)=-1 1 In(1+x) 1 (1-x²) 1 (1-x²) y' = y' + y' + -y+ tanx, y(-/4)=2 -y= tanx, y(1/3) = -1 -y= tanx, y(-/4) = 2 A. (-1,0) π 2 B.(1, (⁰.1) D. (-1,1)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Match IVP with corresponding interval of existence and uniqueness

Match each initial value problem with the corresponding interval of existence and uniqueness 1 In(1+x) -y+ tanx, y(¹/3)=-1 1 In(1+x) 1 (1-x²) 1 (1-x²) y' = y' + y' + -y+ tanx, y(-/4)=2 -y= tanx, y(1/3)=-1 -y= tanx, y(-/4) = 2 A. (-1,0) π 2 B.(1, (₁. =) D. (-1,1)
Transcribed Image Text:Match each initial value problem with the corresponding interval of existence and uniqueness 1 In(1+x) -y+ tanx, y(¹/3)=-1 1 In(1+x) 1 (1-x²) 1 (1-x²) y' = y' + y' + -y+ tanx, y(-/4)=2 -y= tanx, y(1/3)=-1 -y= tanx, y(-/4) = 2 A. (-1,0) π 2 B.(1, (₁. =) D. (-1,1)
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