Mass percent of an element in a compound represents _________________________. Answers: the total grams of the element in the compound   the ratio of the grams of one element in the compound related to the grams of one mole of the whole compound   the ratio of grams of one element in a compound related to grams of another element in the compound   the ratio of moles of one element in a compound related to one mole of the whole compound

Q: What is the empirical formula of a substance that consists of 5.687 g of copper and 1.431 g of…

A:

Q: A mineral sample is obtained from a region of the country that has high arsenic contamination. An…

A: Given :-  Percent composition of Zn = 23.4 %  Percent composition of As = 53.7%  Percent composition…

Q: What is the molecular formula of a compound with the empirical formula As, O, and a formula mass of…

A: Given the molar mass and empirical formula of the compound. By using this, determine molecular…

Q: A sample of sulfolane, C.H3O,S, contains 5.00 x 1024 atoms. How many moles of sulfolane are in the…

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Q: Determine the empirical and molecular formula for a compound that gives the following percentages…

A: Assuming we have 1 mole of compound Hence mass of compound = 1 X molar mass = 98.96 g Since the mass…

Q: What is the mass in grams of each of the following? 1.   1.67 x 1015 atoms of Mn 2.    6.45 x 1023…

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Q: A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is…

A: Given,Percent of B in the compound = 40.28 %Percent of N in the compound = 52.20 %Percent of H in…

Q: Suppose you have two samples that are equal in weight, 24.824.8 g VV and 24.824.8 g Cr2O3Cr2O3.…

A: Given, Mass of V = 24.8g. Mass of Cr2O3 = 24.8g.

Q: A compound is composed of 73.1 % G e and 26.9 % O. What is the empirical formula?

A: Given : Mass percent of Ge = 73.1 %  And mass percent of O = 26.9 % Since the compound contains only…

Q: What is the difference between an empirical formula and a molecular formula? Provide an example.

A: There are three types of chemical formulas:-  Empirical formula is the simplest whole number of…

Q: 91. Calculate the mass in grams of each of the following samples. a 10,000,000,000 nitrogen…

A: as per Q&A guidelines of portal I solve first three parts of the question because it comes under…

Q: What is the mass percent of bromine in lithium bromide?? 1.47.6% 2.52.4% 3.92.01% 4.7.99%…

A: Answer: option 3) 92.01 % is the mass percent of bromine in lithium bromide.

Q: What is the empirical formula of a compound with 54.53% carbon, 9.15% hydrogen, and 36.32% oxygen…

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Q: A compound is 80.0% carbon and 20.0% hydrogen by mass. Assume a 100.-g sample of this compound. The…

A: Given, Mass % of C = 80.0 % Mass % of H = 20.0 % Mass of the compound = 100 g Empirical formula of…

Q: Complete the table below for calculating the molar mass of the compound carbon tetrachloride. Molar…

A: The complete table for the molar mass of the compound carbon tetrachloride is given below, 1mole of…

Q: a. Two compounds have the same composition: 92.25% C and 7.75% H. Obtain the empirical formula…

A: Empirical formula is the simplest formula of a compound where atoms of participating elements are…

Q: 5. Determine the empirical and molecular formula of a compound whose composition is 85.7% C and…

A:

Q: How many C atoms are in 1.3 x 10² mol of sucrose? Be sure your answer has the correct number of…

A: 1 mole = 6.022 x 1023 entities1 mole of compound AB contain 1 mole A and 1 mole of B 1 mole of…

Q: 3. How many moles are represented by 3.01 · 10²24 oxygen atoms? 2 moles 5 moles 250 moles 10 moles

A: One mole has 6.022 x 1023 Therefore 10.0moles will have 10x 6.022 x 1023 =6.022 x 1024 6.022 x 1023…

Q: How many Ne atoms are contained in 32.0 g of the element? 1.07 x 10-21 atoms 3.88 x 1026 atoms O…

A: The question is based on mole concept.we need to calculate number of atoms present in given quantity…

Q: A compound is 54.53% C,54.53% C, 9.15% H,9.15% H, and 36.32% O36.32% O by mass. What is its…

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Q: Mass of Atomic Molar Component elements % Composition Compound element Weight Mass CACO3 Total Molar…

A: The formula of calcium carbonate is CaCO3. The elements present in CaCO3 are calcium, Ca; carbon, C…

Q: Br A) What is the molecular formula for this compound? B) What is the empirical formula for this…

A: A Molecular formula  represent the total number of atoms of each element in each molecule of a…

Q: a. How many molecules of carbon dioxide are present in 4.99 moles of this compound? molecules 22 b.…

A: 1 mol = 6.022 x 1023 moleculesThus,1 molecule =  mol

Q: compound has the mass percent data given below . Determine its empirical formula. 32.43 % carbon by…

A: Empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in…

Q: Part D. A 28.50 g sample of a compound of carbon, sulfur, hydrogen, and combusted (burned). 35.25 g…

A:

Q: Determine the empirical formula of a compound having the following percent composition by mass: K:…

A: Given value, %K=24.74% , MOLAR MASS= 39 g mol-1 %Mn=34.76 %, molar mass=54.938 g mol-1 % O = 40.50…

Q: Aluminium has a density of 2.70 | g/cm3 . How many moles of aluminum are in a 13.2 cm3 block of the…

A: Density :- Density of a substance is its amountof mass per unit volume . So , density is the…

Q: Which of the following can be considered an empirical formula? Explain how you know. CH4 C2H8 C2H6…

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Q: How many moles (of molecules or formula units) are in each sample? 42.59 g CF2Cl2 Express your…

A: One mole contains Avagadro number of atoms. That is, 6.022x1023 atoms. Mass of one mole is called…

Q: Calculate the % composition by mass of each element in phosphorus oxychloride POCl3. Keep at least…

A: Mass composition explanation the amount  of each elements present in whole sample.

Q: A compound contains 28.2% nitrogen, 20.8% phosphorous, 8.10% hydrogen, and 42.9% oxygen. Determine…

A: The elements present in the compounds are nitrogen, phosphorous, hydrogen and oxygen. Let the…

Q: A compound has the following elemental analysis: Element % composition C 48.65 H 8.11 O 43.24…

A: Element %  of  C = 48.65 % = 48.65 gElement %  of  H = 8.11 % = 8.11 gElement %  of  O = 43.24 % =…

Q: A compound is 7.7% (by mass) hydrogen and 92.7 % carbon. It has a molecular weight of 52 g/mole.…

A: Empirical formula are the formula which represent simplest ratio of an element present in a given…

Q: A compound is 54.53% C, 9.15% H, and 36.32% O by mass. What is its empirical formula? Insert…

A: In the given question we have to find out the empherical formula of the compound. Here, we have to…

Q: Calculate the molar mass of the following substances. Molar Mass = b. Mg3(PO4)2 Molar Mass = c.…

A: Molar mass of given compounds can be calculated as:

Q: A compound is determined to be 51.8% chlorine, 1.47% hydrogen, and 46.7% oxygen by weight. The…

A: Welcome to bartleby ! Introduction : We have to calculate the molecular formula .

Q: Determine the empirical formula for a compound containing 40% carbon, 6.7% hydrogen and 53.3%…

A: Carbon = 40%  Hydrogen = 6.7 %  Oxygen = 53.3%  Let there be 100 g of compound , then,  Carbon = 40…

Q: - 1 Compound X has a molar mass of 86.08 g-mol and the following composition: element 0 carbon mass…

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Q: If the molecular weight of the compound is 58.12 g / mol , what is the molecular formula of the…

A: We have to determine the chemical formula of the compound.

Q: 4. What is the mass percent composition? Why is it useful?

A: Mass percent of each type of element in a compound is called the mass percent composition of the…

Q: 1. How many MOLECULES of dinitrogen tetroxide are present in 4.82 moles of this compound ?

A: Since you have asked multiple question, we will solve the firstquestion for you. If you want any…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.