Mass is proportional to length cubed: m = kl where k Is a constant. This model of growth is reasonable because the lamb gets thicker as it gets longer, growing in three dimensional space. At the Initial and final points, m, = kl³ and me = kl³, so m₁ / m₁ = (lf / lf) ³. Length changes by 12.9%. We know that 12.9% off means 0.129 times . So we have l=₁+0.129 e, ylelding = 1+0.129 l₁. From this, we have l³ = 1.129 And finally, mass Increases by 15.3 kg: m; + 15.3 kg = me e.³.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Mass is proportional to length cubed: m = k/³ where k is a constant. This model of growth is reasonable because the lamb gets thicker as It gets longer, growing in
three dimensional space.
At the Initial and final points, m₁ = kl ³ and m = kle³, so
m₁ / m₁ = (le/ l₁) ³.
Length changes by 12.9%. We know that 12.9% of means 0.129 times l. So we have
le = ₁ + 0.129
₁ ylelding = 1+0.129
l₁.
From this, we have
₂³ = 1.129
And finally, mass increases by 15.3 kg:
m₁ + 15.3 kg = m₂
Transcribed Image Text:Step 3 Mass is proportional to length cubed: m = k/³ where k is a constant. This model of growth is reasonable because the lamb gets thicker as It gets longer, growing in three dimensional space. At the Initial and final points, m₁ = kl ³ and m = kle³, so m₁ / m₁ = (le/ l₁) ³. Length changes by 12.9%. We know that 12.9% of means 0.129 times l. So we have le = ₁ + 0.129 ₁ ylelding = 1+0.129 l₁. From this, we have ₂³ = 1.129 And finally, mass increases by 15.3 kg: m₁ + 15.3 kg = m₂
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