mass е relative (amu) abundance 111.9 90.3% 118.9 9.7%

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**Title: Analysis of Tin Isotopes from Planetesimal 98765 ALEKS**

A robotic spacecraft returned samples from the planetesimal 98765 ALEKS, located in the outer Solar System. Mass-spectroscopic analysis produced the following data on the isotopes of tin in these samples:

| Isotope | Mass (amu) | Relative Abundance |
|---------|------------|--------------------|
| \(^{112}\text{Sn}\) | 111.9        | 90.3%                |
| \(^{119}\text{Sn}\) | 118.9        | 9.7%                 |

**Instructions:**

Use these measurements to complete the entry for tin in the Periodic Table that would be used on 98765 ALEKS. Round your entry for the atomic mass to 3 significant digits.

**Caution:**

Your correct answer will have the same format but not necessarily the same numbers as the entry for tin in the Periodic Table we use here on Earth.

*Note: The isotopic data provides a guide for scientists to determine the average atomic mass of tin on this specific celestial body based on the given isotopic composition.*
Transcribed Image Text:**Title: Analysis of Tin Isotopes from Planetesimal 98765 ALEKS** A robotic spacecraft returned samples from the planetesimal 98765 ALEKS, located in the outer Solar System. Mass-spectroscopic analysis produced the following data on the isotopes of tin in these samples: | Isotope | Mass (amu) | Relative Abundance | |---------|------------|--------------------| | \(^{112}\text{Sn}\) | 111.9 | 90.3% | | \(^{119}\text{Sn}\) | 118.9 | 9.7% | **Instructions:** Use these measurements to complete the entry for tin in the Periodic Table that would be used on 98765 ALEKS. Round your entry for the atomic mass to 3 significant digits. **Caution:** Your correct answer will have the same format but not necessarily the same numbers as the entry for tin in the Periodic Table we use here on Earth. *Note: The isotopic data provides a guide for scientists to determine the average atomic mass of tin on this specific celestial body based on the given isotopic composition.*
Expert Solution
Step 1

Average Atomic mass =

= (M1X1 + M2X2)/(X1+X2)

= (111.9×90.3 + 118.9×9.7)/100

= 112.579 amu

= 113

 

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