Mass 1 and mass 2 are connected to the opposite ends of a string of negligible mass that passes through a frictionless tube (as shown). Due to gravity, m2 pulls the string down ward thereby pulling m1 closer to the tube. This unbalance force within the system can be equalized by spinning m1 horizontally by way of holding the tube to generate centripetal force which will create equilibrium. At what linear velocity should m1 be spun to create equilibrium?
Mass 1 and mass 2 are connected to the opposite ends of a string of negligible mass that passes through a frictionless tube (as shown). Due to gravity, m2 pulls the string down ward thereby pulling m1 closer to the tube. This unbalance force within the system can be equalized by spinning m1 horizontally by way of holding the tube to generate centripetal force which will create equilibrium. At what linear velocity should m1 be spun to create equilibrium?
Related questions
Question
Please answer the following questions with solutions
Transcribed Image Text:PS - UCM Horizontal
m1 = 0.25 kg
O
m2 = 0.75 kg
Mass 1 and mass 2 are connected to the opposite ends of a string of negligible mass that passes through
a frictionless tube (as shown). Due to gravity, m2 pulls the string down ward thereby pulling m1 closer to
the tube. This unbalance force within the system can be equalized by spinning m1 horizontally by way of
holding the tube to generate centripetal force which will create equilibrium.
At what linear velocity should m1 be spun to create equilibrium?
What is the tension on the string when there is equilibrium?
L=0.80 m
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
