Please answer number 1, please show work. Show the formula used, etc etc. Marvin was doing a study comparing the populationgrowth of his hometown in the early twentieth centurywith its population growth in the early 1980s.When he came across the two graphs shown here, Marvinnoticed that the first graph appeared to be steeper thanthe second. He concluded that the population wasgrowing faster at the beginning of the century than it wasin the early 1980s.Population (in thousands)7877T76-751900 1904 1908 1912YearPopulation (in thousands)90-8886L1980 1981 1982 1983Year1. Use the first graph to calculate the average increasein population per year for the interval from 1900to 1912.

The population growth model for a current time t is expressed as: Pt=P0ertPt=current populationP0=initial populationr=rate of growth in %t=time from initial period From the graphical representation, it is observed that the population in the periods of 1900 and 1912 are approximately 75.1 and 77.2 thousand. Moreover, the time difference between the period 1900 and 1912 is, t=1912-1900=12. Considering Pt=1912=75.1, P0=75.1, the population growth is modeled as: 77.2=75.1×e12r⇒e12r≈1.02796⇒lne12r=ln1.02796⇒12r × lne=0.027576⇒12r≈0.027576 since lne=1⇒r≈0.0023 or 0.23% So the annual rate of growth (i.e., the average increase in population per year) is 0.23% approximately.