orbit by the period.8.64 x 10 sLEARN MOREREMARKS Earth's motion around the Sun was neglected; that requires using Earth's "sidereal" period(about four minutes shorter). Notice that Earth's mass could be found by substituting the Moon's distanceand period into this form of Kepler's third law.QUESTION If the satellite was placed in an orbit three times farther away, about how long would ittake to orbit the Earth once? Answer in days, rounding to one significant figure.daysEXERCISEHINTS:GETTING STARTEDI'M STUCK!Mars rotates on its axis once every 1.02 days (almost the same as Earth does).(a) Find the distance from Mars at which a satellite would remain in one spot over the Martiansurface. (Use 6.42 x 1023kg for the mass of Mars.)(b) Find the speed of the satellite.m/sNeed Help?Read It

Time , T = 1.02 days 1 day = 86400 sec 1.02 days = 88128 sec Mass of mars , m = 6.42 x 1023 kg To…

Mars rotates on its axis once every 1.02 days (almost the same as Earth does). (a) Find the distance from Mars at which a satellite would remain in one spot over the Martian surface. (Use 6.42 x 1023 kg for the mass of Mars.) (b) Find the speed of the satellite. m/s

Mars rotates on its axis once every 1.02 days (almost the same as Earth does). (a) Find the distance from Mars at which a satellite would remain in one spot over the Martian surface. (Use 6.42 x 1023 kg for the mass of Mars.) (b) Find the speed of the satellite. m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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