Maria is an independent consultant who works diligently to find clients. She averages 4.9 consulting jobs per month. Assume that the number of consulting jobs that Maria lands each month can be described by a Poisson distribution. What is the probability that Maria has two or fewer consulting jobs in the next month?

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Maria is an independent consultant who works diligently to find clients. She
averages 4.9 consulting jobs per month. Assume that the number of consulting
jobs that Maria lands each month can be described by a Poisson distribution.
What is the probability that Maria has two or fewer consulting jobs in the next
month?
Round your answer to three decimal places of accuracy.
Your Answer:
Answer
Transcribed Image Text:Maria is an independent consultant who works diligently to find clients. She averages 4.9 consulting jobs per month. Assume that the number of consulting jobs that Maria lands each month can be described by a Poisson distribution. What is the probability that Maria has two or fewer consulting jobs in the next month? Round your answer to three decimal places of accuracy. Your Answer: Answer
Expert Solution
Step 1

Given,

The average number of consulting job per month λ=4.9

Let X denotes the number of consulting job that Maria lends each month.

Therefore X~Poisson(λ=4.9)

The probability mass function of X is given as-

PX=e-λ×λxx!=e-4.9×4.9xx!

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