Many genetic disorders, such as cystic fibrosis and sickle-cell disease are due to mutations in a recessive allele. You have sampled an isolated population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate: 1d. the frequency of the "AA" genotype (round to the nearest hundredth)
Many genetic disorders, such as cystic fibrosis and sickle-cell disease are due to mutations in a recessive allele. You have sampled an isolated population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate:
1d. the frequency of the "AA" genotype (round to the nearest hundredth)
We may use the Hardy-Weinberg equation to estimate the frequency of "AA" genotype in a population.
In population genetics, the theory of Hardy–Weinberg, also called the Hardy–Weinberg theorem, suggests that in the absence of any other evolutionary factors, the allelic frequencies and genotypic frequencies in a population stays constant from generation to generation.
For a population in genetic equilibrium:
p + q = 1 (The sum of the frequencies of both alleles is 100%.)
here, p = the frequency of the dominant allele (represented here by A)
q = the frequency of the recessive allele (represented here by a)
So the Hardy-Weinberg equation is expressed as:
p2 + 2pq + q2 = 1; where;
p2 = frequency of AA (homozygous dominant)
2pq = frequency of Aa (heterozygous)
q2 = frequency of aa (homozygous recessive)
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