**Question 3: Memory Allocation in C Structs**In this question, we are tasked with finding out how many bytes are allocated for the program variables in the provided C program segment.### Program Segment:```cStruct sID { int number; double cost; double *barcode; /* assume int is 4 bytes and double is 8 bytes long */};struct sID stud[3], *item;```### Explanation:1. **Structure Definition (`struct sID`):** - **int number**: Takes 4 bytes. - **double cost**: Takes 8 bytes. - **double *barcode**: A pointer (typically 8 bytes on a 64-bit system).2. **Total Size of struct sID:** - Total = 4 (int) + 8 (double) + 8 (pointer) = 20 bytes per structure.3. **Array of Structures (`struct sID stud[3]`):** - There are three instances of `struct sID`. - Total Memory = 3 * 20 = 60 bytes.4. **Pointer to Structure (`struct sID *item`):** - This is just a pointer, typically 8 bytes on a 64-bit system.### Total Memory Allocated:- Memory for `stud[3]`: 60 bytes- Memory for `*item`: 8 bytesThus, the total memory allocated for all the variables in the segment is **68 bytes**.

Given :- A Structure is defined in c (programming language used) Struct sID { int number; double cost; double *barcode; } Struct sID stud[3], *item; Need to compute the number of bytes are allocated for the program variable in the above given program segement The required solution is mention in step (2) below as, Solution :- It is given in question for assuming the integer datatype will take 4 bytes and double is 8 bytes long and given structure sID along with the definition is given as, Struct sID { int number; //int takes 4 bytes double cost; //double takes 8 bytes double *barcode; //double takes 8 bytes } Struct sID stud[3], *item; Thus, required structure size would be , => sum of size of each data type => ( 4 + 8 + 8 ) => (4 + 16) => 20 Therefore, the number of bytes are allocated for the program variable in the above given program segement would be 20 only