Manipulate equation 3 to match the H20 part of the overall equation. What will be the new AH value? 3) H2(g) + ¿O2(g)→ H2O(g) AH = -241.8 kJ goal equation: 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH° = [ ? ] kJ Enter either a + or - sign AND the magnitude. Do not round. Enter

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Chapter1: Chemical Foundations
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Manipulate equation 3 to match the H2O part
of the overall equation. What will be the new
AH value?
3) H2(g) + ¿O2(g) → H,0(g) AH = -241.8 kJ
%3D
goal equation:
4NH3(g) + 502(g) → 4NO(g) + 6H2O(g)
AH° = [ ? ] kJ
%3D
Enter either a + or - sign AND the magnitude. Do not round.
Enter
Transcribed Image Text:elp acellus_engine.html?ClassID=2134898241# Manipulate equation 3 to match the H2O part of the overall equation. What will be the new AH value? 3) H2(g) + ¿O2(g) → H,0(g) AH = -241.8 kJ %3D goal equation: 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH° = [ ? ] kJ %3D Enter either a + or - sign AND the magnitude. Do not round. Enter
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