Make 200 mL of 0.5 M HEPES pH 7.3 using 1.0 M HEPES-acid (pK, -7.6) and 1.0 M HEPES-base... Select the correct answer below: O Combine 73 mL of HEPES base with 127 mL of HEPES acid O Combine 34 mL of HEPES base with 66 mL of HEPES acid and 100 mL of water O Combine 10 mL of HEPES base with 40 mL of HEPES acid and 150 mL of water O Combine 63 mL of HEPES base with 27 mL of HEPES acid and 100 mL of water
Make 200 mL of 0.5 M HEPES pH 7.3 using 1.0 M HEPES-acid (pK, -7.6) and 1.0 M HEPES-base... Select the correct answer below: O Combine 73 mL of HEPES base with 127 mL of HEPES acid O Combine 34 mL of HEPES base with 66 mL of HEPES acid and 100 mL of water O Combine 10 mL of HEPES base with 40 mL of HEPES acid and 150 mL of water O Combine 63 mL of HEPES base with 27 mL of HEPES acid and 100 mL of water
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1: Determine the volumes of each species present in the solution:
Given,
Molarity of HEPES = 0.5 M
volume of the solution = 200 mL
pH of the solution = 7.3
Molarity of HEPES-acid = 1.0 M
Molarity of HEPES-base = 1.0 M
pKa of HEPES-acid = 7.6
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