main.c 1. Leap Year Detector 1 #include by CodeChum Admin 2 3 int isleapYear(int); Let's try to find out whether a year has 365 or 366 days. To do this, we need to create a 5- int main(void) { leap year detector! // TODO: Write your code here 7 8 return 0; Conditions for a leap year: 9 } 1.) year must be divisible by 4 and not divisible by 100 2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year. 10 11- int isleapYear(int n) { if( (n % 4 == 0 && n % 100 != 0) |I (n % 100 == 0 && n % 400 == 0) 12- 13 14 15 - ) { Instructions: 16 return 1; } 17 1. You are provided with the isLeapYear() function which is already declared and defined for you. 18 19 return 0; 20 3 2. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.
main.c 1. Leap Year Detector 1 #include by CodeChum Admin 2 3 int isleapYear(int); Let's try to find out whether a year has 365 or 366 days. To do this, we need to create a 5- int main(void) { leap year detector! // TODO: Write your code here 7 8 return 0; Conditions for a leap year: 9 } 1.) year must be divisible by 4 and not divisible by 100 2.) If year is divisible by 100, it must be divisible by 400 for it to be a leap year. 10 11- int isleapYear(int n) { if( (n % 4 == 0 && n % 100 != 0) |I (n % 100 == 0 && n % 400 == 0) 12- 13 14 15 - ) { Instructions: 16 return 1; } 17 1. You are provided with the isLeapYear() function which is already declared and defined for you. 18 19 return 0; 20 3 2. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Hello! Please help me find the C language code of this. Thank You!
Transcribed Image Text:1. You are provided with the isLeapYear()
function which is already declared and
defined for you.
main.c
C
1
#include<stdio.h>
2
2. Your task is to ask the user for a year
3
int isleapYear(int);
and then call the isLeapYear function to
check whether the year is a leap year
4
5- int main(void) {
or not.
// TODO: Write your code here
7
return 0;
}
8
9.
Input
10
11- int isleapYear(int n) {
1. Year to be checked
if(
(n % 4 == 0 && n % 100 != 0) II
(n % 100 == 0 && n % 400 ==
12
13
Output
14
0)
15
) {
If a certain year is a leap year, print "
<INSERT_YEAR_HERE> is a leap year"
16
return 1;
}
17
Otherwise, print "<INSERT_YEAR_HERE> is
18
not a leap year"
19
return 0;
20
Enter year: 2020
2020 is a leap year
Transcribed Image Text:main.c
> + c
1. Leap Year Detector
1 #include<stdio.h>
by CodeChum Admin
2
3
int isleapYear(int);
Let's try to find out whether a year has 365
or 366 days. To do this, we need to create a
4
5. int main(void) {
leap year detector!
6
// TODO: Write your code here
7
return 0;
}
8
Conditions for a leap year:
9.
1.) year must be divisible by 4 and not
divisible by 100
10
11- int isleapYear(int n) {
if(
(n % 4 ==
2.) If year is divisible by 100, it must be
12
divisible by 400 for it to be a leap year.
13
O && n % 100 != 0) ||
(n % 100 == 0 && n % 400 == 0)
) {
return 1;
}
14
15
Instructions:
16
17
1. You are provided with the isLeapYear()
function which is already declared and
defined for you.
18
19
return 0;
20
2. Your task is to ask the user for a year
and then call the isLeapYear function to
check whether the year is a leap year
or not.
>
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