Main Menu Contents Grades Course Contents... HW #6 (due Mon 2/27 at 10am) elevator02_block1+hand-down.problem Block 1 (9 kg) is setting on the floor of an elevator. A hand pushes vertically down on block 1 with a force of 14.0 N. The elevator is moving downward with a decreasing speed and the magnitude of the acceleration is 9 m/s2. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the the "j" component. NET force on Block 1 Fnet101+81 JN Computer's answer now shown above. Incorrect. Tries 2/2 Previous Tries FORCES on BLOCK 1 Weight force on block 1 by Earth, WIE= i+ IN Submit Answer Tries 0/2 Normal force on block 1 by Hand +14 N1H 0 IN The magnitude of N1H is given in the problem and points down (negative y-value). Submit Answer Incorrect. Tries 1/2 Previous Tries Normal force on block 1 by Surface. N1S 0 1+ 4.2 jN The sum of the W1E, N1H, and N1S forces must equal the net force on block 1. Submit Answer Incorrect. Tries 1/2 Previous Tries Post Discussion.

Main Menu Contents Grades Course Contents... HW #6 (due Mon 2/27 at 10am) elevator02_block1+hand-down.problem Block 1 (9 kg) is setting on the floor of an elevator. A hand pushes vertically down on block 1 with a force of 14.0 N. The elevator is moving downward with a decreasing speed and the magnitude of the acceleration is 9 m/s2. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the the "j" component. NET force on Block 1 Fnet101+81 JN Computer's answer now shown above. Incorrect. Tries 2/2 Previous Tries FORCES on BLOCK 1 Weight force on block 1 by Earth, WIE= i+ IN Submit Answer Tries 0/2 Normal force on block 1 by Hand +14 N1H 0 IN The magnitude of N1H is given in the problem and points down (negative y-value). Submit Answer Incorrect. Tries 1/2 Previous Tries Normal force on block 1 by Surface. N1S 0 1+ 4.2 jN The sum of the W1E, N1H, and N1S forces must equal the net force on block 1. Submit Answer Incorrect. Tries 1/2 Previous Tries Post Discussion.

Name: Omar Amro (Student section: 9)Main Menu Contents Grades SyllabusCours
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Description: Omar Amro (Student section: 9)Main Menu Contents Grades SyllabusCourse Contents> ... > HW #6 (due Mon 2/27 at 10am) elevator02_block1+hand-down.problemTimer NotesBlock 1 (9 kg) is setting on the floor of an elevator. A hand pushes vertically down on

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Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Omar Amro (Student section: 9)
Main Menu Contents Grades Syllabus
Course Contents> ... > HW #6 (due Mon 2/27 at 10am) elevator02_block1+hand-down.problem
Timer Notes
Block 1 (9 kg) is setting on the floor of an elevator. A hand pushes vertically down on block 1 with a force of 14.0 N. The elevator is moving downward with a decreasing speed and the magnitude of the acceleration is 9 m/s².
On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the
the "j" component.
NET force on Block 1
Fnet1 = 01 +81jN
Computer's answer now shown above. Incorrect. Tries 2/2 Previous Tries
FORCES on BLOCK 1
Weight force on block 1 by Earth
WIE =
i+
Submit Answer Tries 0/2
Normal force on block 1 by Hand
N1H = 0
i + 14
jN
The magnitude of N1H is given in the problem and points down (negative y-value).
Submit Answer
Incorrect. Tries 1/2 Previous Tries
jN
Normal force on block 1 by Surface
N1S 0
i+ 4.2 jN
The sum of the W1E, N1H, and N1S forces must equal the net force on block 1.
Submit Answer Incorrect. Tries 1/2 Previous Tries
Post Discussion
Type here to search
OCLOS G
Address
C
Act
47°F Partly

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