Mai and Jada are solving the equation 2r-71 = 15 using the quadratic formula but found different solutions. Mai wrote: -7+,/7-4(2)(-15) 2(2) -7+,/49-(-120) 4. -7+V169 4. -713 エー-5 or z= } Jada wrote: --7)+/-7-4(2)(-15) 2(2) 74/-49-(-120) 4. 74 71 a. If this equation is written in standard form, az + br + c=0 what are the values of a, b, and c? Type the answers in the boxes below. b. Do you agree with either of them?
Mai and Jada are solving the equation 2r-71 = 15 using the quadratic formula but found different solutions. Mai wrote: -7+,/7-4(2)(-15) 2(2) -7+,/49-(-120) 4. -7+V169 4. -713 エー-5 or z= } Jada wrote: --7)+/-7-4(2)(-15) 2(2) 74/-49-(-120) 4. 74 71 a. If this equation is written in standard form, az + br + c=0 what are the values of a, b, and c? Type the answers in the boxes below. b. Do you agree with either of them?
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Problem attached as picture below. (Algebra 1)
![**Solving Quadratic Equations Using the Quadratic Formula**
Mai and Jada are solving the equation \(2x^2 - 7x = 15\) using the quadratic formula but found different solutions.
**Mai's Work:**
\[ x = \frac{-7 \pm \sqrt{7^2 - 4(2)(-15)}}{2(2)} \]
\[ x = \frac{-7 \pm \sqrt{49 - (-120)}}{4} \]
\[ x = \frac{-7 \pm \sqrt{169}}{4} \]
\[ x = \frac{-7 \pm 13}{4} \]
\[ x = -5 \quad \text{or} \quad x = \frac{3}{2} \]
**Jada's Work:**
\[ x = \frac{(-7) \pm \sqrt{7^2 - 4(2)(-15)}}{2(2)} \]
\[ x = \frac{7 \pm \sqrt{49 - (-120)}}{4} \]
\[ x = \frac{7 \pm \sqrt{169}}{4} \]
\[ x = \frac{7 \pm 13}{4} \]
**Question:**
a. If this equation is written in standard form, \(ax^2 + bx + c = 0\), what are the values of \(a\), \(b\), and \(c\)?
Type the answers in the boxes below.
\[ a = \_\_\_ \quad b = \_\_\_ \quad c = \_\_\_ \]
b. Do you agree with either of them?
Select the answer from the drop-down list.
---
In the worked examples by Mai and Jada, they both start by correctly identifying the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Then they substitute \(a = 2\), \(b = -7\), and \(c = -15\) into the formula and simplify it step by step.
Both Mai and Jada make a correct substitution and simplification, arriving at the same solutions: \( x = -5 \) or \( x = \frac{3}{2} \).
### Answer Key
a. The values are:
\[ a = 2 \]
\[ b = -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ed70d79-cf0b-4e26-9486-b0570d8d2487%2F28328c69-73e6-42ce-90d3-b0dca907d69c%2Fccu7dor_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Solving Quadratic Equations Using the Quadratic Formula**
Mai and Jada are solving the equation \(2x^2 - 7x = 15\) using the quadratic formula but found different solutions.
**Mai's Work:**
\[ x = \frac{-7 \pm \sqrt{7^2 - 4(2)(-15)}}{2(2)} \]
\[ x = \frac{-7 \pm \sqrt{49 - (-120)}}{4} \]
\[ x = \frac{-7 \pm \sqrt{169}}{4} \]
\[ x = \frac{-7 \pm 13}{4} \]
\[ x = -5 \quad \text{or} \quad x = \frac{3}{2} \]
**Jada's Work:**
\[ x = \frac{(-7) \pm \sqrt{7^2 - 4(2)(-15)}}{2(2)} \]
\[ x = \frac{7 \pm \sqrt{49 - (-120)}}{4} \]
\[ x = \frac{7 \pm \sqrt{169}}{4} \]
\[ x = \frac{7 \pm 13}{4} \]
**Question:**
a. If this equation is written in standard form, \(ax^2 + bx + c = 0\), what are the values of \(a\), \(b\), and \(c\)?
Type the answers in the boxes below.
\[ a = \_\_\_ \quad b = \_\_\_ \quad c = \_\_\_ \]
b. Do you agree with either of them?
Select the answer from the drop-down list.
---
In the worked examples by Mai and Jada, they both start by correctly identifying the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Then they substitute \(a = 2\), \(b = -7\), and \(c = -15\) into the formula and simplify it step by step.
Both Mai and Jada make a correct substitution and simplification, arriving at the same solutions: \( x = -5 \) or \( x = \frac{3}{2} \).
### Answer Key
a. The values are:
\[ a = 2 \]
\[ b = -
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