The problem involves analyzing the net force in the x-direction on a 2.20-kg particle, with the force's magnitude varying over time. This is depicted in a graph where:- The x-axis represents time \( t \) in seconds, ranging from 0 to 5 seconds.- The y-axis represents force \( F(t) \) in newtons, ranging from 0 to 4 newtons.The graph shows a triangular shape of the force plotted against time:- From \( t = 0 \) to \( t = 1 \), the force increases linearly from 0 to 4 N.- From \( t = 1 \) to \( t = 3 \), the force remains constant at 4 N.- From \( t = 3 \) to \( t = 5 \), the force decreases linearly back to 0 N.The questions to solve are:(a) Find the impulse of the force over the 5.00-s time interval.\[ \vec{I} = \boxed{ \ \ \ \ \ } \text{N · s} \](b) Find the final velocity the particle attains if it is originally at rest.\[ \vec{v}_f = \boxed{ \ \ \ \ \ } \text{m/s} \](c) Find its final velocity if its original velocity is \( -2.30 \, \hat{\imath} \) m/s.\[ \vec{v}_f = \boxed{ \ \ \ \ \ } \text{m/s} \](d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.\[ \vec{F}_{\text{avg}} = \boxed{ \ \ \ \ \ } \text{N} \]

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Answered: magnitude of the net force exerted in…

magnitude of the net force exerted in the x direction on a 2.20-kg particle varies in time as shown in the figure below. F(N) 4 3 2 1 ol 1 2 3 4 5 t(s) e

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

The problem involves analyzing the net force in the x-direction on a 2.20-kg particle, with the force's magnitude varying over time. This is depicted in a graph where:

- The x-axis represents time \( t \) in seconds, ranging from 0 to 5 seconds.
- The y-axis represents force \( F(t) \) in newtons, ranging from 0 to 4 newtons.

The graph shows a triangular shape of the force plotted against time:

- From \( t = 0 \) to \( t = 1 \), the force increases linearly from 0 to 4 N.
- From \( t = 1 \) to \( t = 3 \), the force remains constant at 4 N.
- From \( t = 3 \) to \( t = 5 \), the force decreases linearly back to 0 N.

The questions to solve are:

(a) Find the impulse of the force over the 5.00-s time interval.
\[ \vec{I} = \boxed{ \ \ \ \ \ } \text{N · s} \]

(b) Find the final velocity the particle attains if it is originally at rest.
\[ \vec{v}_f = \boxed{ \ \ \ \ \ } \text{m/s} \]

(c) Find its final velocity if its original velocity is \( -2.30 \, \hat{\imath} \) m/s.
\[ \vec{v}_f = \boxed{ \ \ \ \ \ } \text{m/s} \]

(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.
\[ \vec{F}_{\text{avg}} = \boxed{ \ \ \ \ \ } \text{N} \]

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