Answered: magnitude of the force | bartleby

Related questions

Question

Find the magnitude of the force that an electric field of 2.78 N/C exerts on an electron. Answer in units of N.

Expert Solution

Given data

Electric field Effect = 2.78 N/C

Charge of the electron q = 1.6x10^-19 C

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

1. (a) What is the magnitude and direction of an electric field that exerts a 3.105 N upward force on a -1.6 μC charge? |E| = O Upward O Downward (b) What is the magnitude and direction of the force exerted on a 3.65 μC charge by a 250 field that points due east? |F| = O North O East O West N O South N N 2/0 electric
What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 8651 N/C and is directed due north?
An electric field of 11000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -9.1 µC at this spot?
When a shower is turned on in a closed bathroom, the splashing of the water on the bare tub can fill the room's air with negatively charged ions and produce an electric field in the air as great as 1000 N/C. Consider a bathroom with dimensions 2.4 m x 2.6 m x 1.9 m. Along the ceiling, floor, and four walls, approximate the electric field in the air as being directed perpendicular to the surface and as having a uniform magnitude of 760 N/C. Also, treat those surfaces as forming a closed Gaussian surface around the room's air. What are (a) the volume charge density ρ and (b) the number of excess elementary charges e per cubic meter in the room's air?
An electron is placed in a uniform electric field of E = (3.24 x 10e3 N/C) i + (1.35 x 10e3 N/C) j . calculate the magnitude of the electron's instantaneous acceleration. answer in scientific notation
Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 320 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s2)? (b) The electron is initially at rest. What is its speed (in m/s) after 1.10 ✕ 10−8 s?
Inside a radiation therapy device, an electron is in the presence of a uniform electric field with a magnitude of 325 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s2)? m/s2 (b) The electron is initially at rest. What is its speed (in m/s) after 1.25 ✕ 10−8 s? m/s
A proton is released from rest in a uniform electric field of magnitude 406 N/C. (a) Find the electric force on the proton. magnitude 6.496e-17 ✓ N direction in the direction of the electric field (b) Find the acceleration of the proton. magnitude 3.889e10 m/s² direction in the direction of the electric field (c) Find the distance it travels in 2.08 μs. X
17.6. A charged cork ball of mass 1.10 g is suspended on a light string in the presence of a uniform electric field as shown in the figure below. When E = (2.80 î + 5.20 ĵ) ✕ 105 N/C, the ball is in equilibrium at θ = 37.0°. (a) Find the charge on the ball. C(b) Find the tension in the string. N
Inside a cathode ray tube, an electron is in the presence of a uniform electric field with a magnitude of 325 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s²)? m/s² (b) The electron is initially at rest. What is its speed (in m/s) after 1.05 x 10-8 s? m/s
Singly-ionized helium contains two protons and one electron (there are also neutrons, but they have net zero charge and are not pertinent to this problem). Suppose the electron is located a distance of 2.65 × 10^-11 m from the nucleus. Place the nucleus at the origin of your coordinate system and the electron on the positive-x axis. What is the position on the x-axis at which the electric field is zero?
The charge per unit length on a long, straight filament is -93.3 µC/m. (a) Find the electric field 10.0 cm from the filament, where distances are measured perpendicular to the length of the filament. (Take radially inward toward the filament as the positive direction.) MN/C(b) Find the electric field 40.0 cm from the filament, where distances are measured perpendicular to the length of the filament. MN/C(c) Find the electric field 120 cm from the filament, where distances are measured perpendicular to the length of the filament. MN/C

SEE MORE QUESTIONS