magnitude and direction) of the dust particle? points downward and has a magnitude of approximately 66. On a typical clear day, the atmospheric electric field a single electron charge. What is the acceleration (both 100 N/C. Compare the gravitational and electric forces on small dust particle of mass 2.0 × 10-15 g that carries a

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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a single electron charge. What is the acceleration (both
66. On a typical clear day, the atmospheric electric field
points downward and has a magnitude of approximately
65. A particle of charge 2.0 × 10-8 C experiences an
upward force of magnitude 4.0x 10-6N when it is
q=-1.0x 10-8 C is placed there, what is the force on
is the electric field at that point? (b) If a charge
placed in a particular point in an electric field. (a) What
100 N/C. Compare the gravitational and electric forces on
5.4 Electric Field
field?
71. The electric field
2.0x 10 N/C. What
this field?
72. A small piece of
charge of 5.0x 10-7
place the cork in equi
and gravitational forc
it?
a
Ele
73. If the electrc fim
small dust particle of mass 2.0 × 10¬15
g that carries
from a point charge
of
a
of the dust particle?
74. What is the el
magnitude and dire
orbit for hydrogen
67. Consider an electron that is 10-10 m from an alpha
force on the electrc
particle (q = 3.2× 10-19 C). (a) What is the electric
75. (a) What is t
field due to the alpha particle at the location of the electron?
(b) What is the electric field due to the electron at the
location of the alpha particle? (c) What is the electric force
on the alpha particle? On the electron?
a point that is 10
force this electric
placed at that poi
76.
Two po
68. Each the balls shown below carries a charge q and has
a mass m. The length of each thread is l, and at equilibrium,
the balls are separated by an angle 20. How does 0 vary
with q and 1? Show that 0 satisfies
92 =-6.0x 1
the electric fiele
and along the l
force on an ele
|sin(0)² tan(0)
%3D
77. Point ch
16re0gl m
placed 1.0 m
midway betw
93 = 20 µC
%3D
78
Can
a of thule
Transcribed Image Text:a single electron charge. What is the acceleration (both 66. On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 65. A particle of charge 2.0 × 10-8 C experiences an upward force of magnitude 4.0x 10-6N when it is q=-1.0x 10-8 C is placed there, what is the force on is the electric field at that point? (b) If a charge placed in a particular point in an electric field. (a) What 100 N/C. Compare the gravitational and electric forces on 5.4 Electric Field field? 71. The electric field 2.0x 10 N/C. What this field? 72. A small piece of charge of 5.0x 10-7 place the cork in equi and gravitational forc it? a Ele 73. If the electrc fim small dust particle of mass 2.0 × 10¬15 g that carries from a point charge of a of the dust particle? 74. What is the el magnitude and dire orbit for hydrogen 67. Consider an electron that is 10-10 m from an alpha force on the electrc particle (q = 3.2× 10-19 C). (a) What is the electric 75. (a) What is t field due to the alpha particle at the location of the electron? (b) What is the electric field due to the electron at the location of the alpha particle? (c) What is the electric force on the alpha particle? On the electron? a point that is 10 force this electric placed at that poi 76. Two po 68. Each the balls shown below carries a charge q and has a mass m. The length of each thread is l, and at equilibrium, the balls are separated by an angle 20. How does 0 vary with q and 1? Show that 0 satisfies 92 =-6.0x 1 the electric fiele and along the l force on an ele |sin(0)² tan(0) %3D 77. Point ch 16re0gl m placed 1.0 m midway betw 93 = 20 µC %3D 78 Can a of thule
Expert Solution
Step 1

The force experienced by a charge particle in electric field is called electric force.

                                    Fe = q.E

The direction of electric force depends on the nature of charge particle.

The gravitational force is given by,

                     Fg = mg

 

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