Macmillan Learnin If a buffer solution is 0.140 M in a weak acid (K, = 5.4 x 10-5) and 0.500 M in its conjugate base, what is the pH? pH

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**Buffer Solution pH Calculation**

If a buffer solution is 0.140 M in a weak acid (\(K_a = 5.4 \times 10^{-5}\)) and 0.500 M in its conjugate base, what is the pH?

**pH =** [Calculate here]

This question involves determining the pH of a buffer solution using the concentrations of a weak acid and its conjugate base. The acid dissociation constant (\(K_a\)) is provided. To find the pH, use the Henderson-Hasselbalch equation:

\[ \text{pH} = \text{pK}_a + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right) \]

Where:
- \([\text{HA}]\) is the concentration of the weak acid (0.140 M).
- \([\text{A}^-]\) is the concentration of the conjugate base (0.500 M).
- \(\text{pK}_a = -\log K_a\).

**Graph/Diagram Explanation**

There are no graphs or diagrams present in the image. The space provided is intended for the calculation of the pH value based on the given data.
Transcribed Image Text:**Buffer Solution pH Calculation** If a buffer solution is 0.140 M in a weak acid (\(K_a = 5.4 \times 10^{-5}\)) and 0.500 M in its conjugate base, what is the pH? **pH =** [Calculate here] This question involves determining the pH of a buffer solution using the concentrations of a weak acid and its conjugate base. The acid dissociation constant (\(K_a\)) is provided. To find the pH, use the Henderson-Hasselbalch equation: \[ \text{pH} = \text{pK}_a + \log \left(\frac{[\text{A}^-]}{[\text{HA}]}\right) \] Where: - \([\text{HA}]\) is the concentration of the weak acid (0.140 M). - \([\text{A}^-]\) is the concentration of the conjugate base (0.500 M). - \(\text{pK}_a = -\log K_a\). **Graph/Diagram Explanation** There are no graphs or diagrams present in the image. The space provided is intended for the calculation of the pH value based on the given data.
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