Macmillan Learn The rate constant for this second-order reaction is 0.780 M-s¯¹ at 300 °C. A-products How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.240 M? t= S
Macmillan Learn The rate constant for this second-order reaction is 0.780 M-s¯¹ at 300 °C. A-products How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.240 M? t= S
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Macmillan Learnin
The rate constant for this second-order reaction is 0.780 M¹s¹ at 300 °C.
*
A - products
How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.240 M?
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Transcribed Image Text:Macmillan Learnin
The rate constant for this second-order reaction is 0.780 M¹s¹ at 300 °C.
*
A - products
How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.240 M?
AM O
C
11
4 101
4
R
F
f5 1
%
V
5
T
G
a
f6
6
B
27
#
Y
H
&
U
fg
J
8
11
N M
fg
ỷ
9
K
f10
▶II
O
O
L
>
P
alt
69°F
f12
✈
?
+
[
1
insert
←
]
pause
ctrl
3:50 PM
9/27/2022
prt sc
backspace
S
BANG & OLUFSEN
13
delete
home
enter
pe
T shif
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given,
A -----> Product
Reaction follows second order kinetics.
Great constant (k) = 0.780 M-1.s-1
Initial concentration of A = [A]o = 0.800 M
Concentration of A later = [A]t = 0.240 M
Time (t) = ? s
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