HALP m + n = 2k + 2k = 4k therefore adding even numbers always gives an even number.The above is wrong because.... it doesn't consider the case when adding to odd numbers m and n are different so you cannot use 2k for both it doesn't consider what m and n are for particular values in the integers it doesn't consider the case when m is even and n is odd

Yes , As we know that adding of two even is always a even number

Answered: m + n = 2k + 2k = 4k therefore adding…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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HALP

m + n = 2k + 2k = 4k therefore adding even numbers always gives an even number.

The above is wrong because....

		it doesn't consider the case when adding to odd numbers
		m and n are different so you cannot use 2k for both
		it doesn't consider what m and n are for particular values in the integers
		it doesn't consider the case when m is even and n is odd

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