m, m2 1. A force F=100N is applied at an angle 0=60° with the horizontal to a small block of mass m,=1kg to make it slide along the top of a larger block of mass m2=10kg. The coefficient of kinetic friction between the blocks is µ=0.4. The larger block slides without friction along a horizontal surface. The blocks start from rest with the smaller block at one end of the larger block. а. On the diagram below, draw and label all the forces acting on each block. m
m, m2 1. A force F=100N is applied at an angle 0=60° with the horizontal to a small block of mass m,=1kg to make it slide along the top of a larger block of mass m2=10kg. The coefficient of kinetic friction between the blocks is µ=0.4. The larger block slides without friction along a horizontal surface. The blocks start from rest with the smaller block at one end of the larger block. а. On the diagram below, draw and label all the forces acting on each block. m
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Transcribed Image Text:m1
m2
A force F=100N is applied at an angle 0=60° with the horizontal to a small block of mass m1=1kg to make
it slide along the top of a larger block of mass m2=10kg. The coefficient of kinetic friction between the
1.
blocks is µ=0.4. The larger block slides without friction along a horizontal surface. The blocks start from
rest with the smaller block at one end of the larger block.
On the diagram below, draw and label all the forces acting on each block.
а.
m2
b. Write an expression for the normal force applied by the surface to block mı.
С.
Find the acceleration of each block, a1 and a2, relative to the horizontal surface.
d. Find the coefficient of friction required on the second surface so that block m2 does not move.
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