m₁ = 4.00 kg a = 33.1° μs = 0.40 HK = 0.20 a) What is the maximum mass m₂ so that it will not go down? and What is the minimum mass m₂ so that it will not go up? b) If mass m₂ is twice that of maximum mass at question a), how much time will it take for m₂ to go down by a distance of 3 m? c) If m₁ is sliding up at constant speed of 2 m/s, what is mass m₂?

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Chapter1: Units, Trigonometry. And Vectors
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INSTRUCTIONS:
- Show the 'free body diagrams' completely.
- Show all equations obtained from the free body diagrams.
- Show all solutions completely.
m₁ = 4.00 kg
α = 33.1°
Hs = 0.40
HK = 0.20
a) What is the maximum mass m₂ so that it will not
go down? and What is the minimum mass m₂ so
that it will not go up?
m₁
α
b) If mass m₂ is twice that of maximum mass at
question a), how much time will it take for m₂ to go down by a distance of 3 m?
c) If m₁ is sliding up at constant speed of 2 m/s, what is mass m₂?
m₂
Transcribed Image Text:INSTRUCTIONS: - Show the 'free body diagrams' completely. - Show all equations obtained from the free body diagrams. - Show all solutions completely. m₁ = 4.00 kg α = 33.1° Hs = 0.40 HK = 0.20 a) What is the maximum mass m₂ so that it will not go down? and What is the minimum mass m₂ so that it will not go up? m₁ α b) If mass m₂ is twice that of maximum mass at question a), how much time will it take for m₂ to go down by a distance of 3 m? c) If m₁ is sliding up at constant speed of 2 m/s, what is mass m₂? m₂
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