ly(x, t = 0)|² = e exp (-). Show that at arbitrary time the probability %D %D density of the packet is lý(x,t)|² : x2 1 where L(t)Vn exp L²(t).
ly(x, t = 0)|² = e exp (-). Show that at arbitrary time the probability %D %D density of the packet is lý(x,t)|² : x2 1 where L(t)Vn exp L²(t).
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Solve the following problem step by step, indicate your procedure and justify each step you give as well as your answer.
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Note ħ=h/2π
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