I ReviewA typical cell has a membrane potential of -70 mV,meaning that the potential inside the cell is 70 mVless than the potential outside due to a layer ofnegative charge on the inner surface of the cell walland a layer of positive charge on the outer surface.This effectively makes the cell wall a chargedcapacitor. Because a cell's diameter is much largerthan the wall thickness, it is reasonable to ignorethe curvature of the cell and think of it as a parallel-plate capacitor.Part AHow much energy is stored in the electric field of a 50-um-diameter cell with a 7.0-nm-thick cell wallwhose dielectric constant is 9.0?Express your answer with the appropriate units.HẢ?-17Uc = 3,905 • 10JSubmitPrevious Answers Request AnswerX Incorrect; Try Again; 2 attempts remaining

Given: The membrane potential is -70 mV or 70×10-3 m. The diameter of the cell is 50 μm. The thickness of the wall is 7.0 nm. The dielectric constant is 9. To determine: The energy stored in electric field. The radius of the cell is r=d2 where r is the radius and d is the diameter of the cell. r=50 μm2r=25 μmr=25×10-6 m The thickness of the wall is t=7×10-9 m. The capacitance of the cell is C=Kε0At ..................................... (1) where C is the capacitance, K is the dielectric constant, A is the area of cell and t is the thickness of cell. The area of the cell is A=4πr2A=4π25×10-6 m2A=7850×10-12 m2 Substitute these values in equation (1) C=9×8.854×10-12 C2/N.m2×7850×10-12 m27×10-9 mC=8.9×10-11 F The energy stored is E=12CV2 where E is the energy and V is the potential. E=12×8.9×10-11 F×70×10-3 m2E=2.2×10-13 J The energy stored in electric field is 2.2×10-13 J.

Answered: LV vall се. Part A ger How much energy…

LV vall се. Part A ger How much energy is stored in the electric field of a 50-µm-diameter cell with a 7.0-nm-thick cell whose dielectric constant is 9.0? lel- Express your answer with the appropriate units. HÀ