LU20 Quiz 13.1 (page 5 of 5) A robot fires a tennis ball to protect itself from an incoming baseball. The trajectory of the tennis ball shot from the robot is given by r(s) = (10- 20s, 10V 3-20V 3s, 15s - 5s2) the position of the robot, and the baseball has a trajectory given by b(t) = (5t, 5V 3t, 10t – 5t2), t> 0 , where r(0) %3D At what time to t0 should the robot fire the tennis ball so that it collides with the baseball? Select one: a. 1 to %3D b. to = 2 C. to = 3 %3D d. to = 1 e. to

Q: 3y3 (2y+3) (y-5)

A: The given expression is

Q: 3x: - 2x2 + 2x3 = 0 6. Solve *, + 2x2 – 3x3 4x1 + x2 + 2x3 = 0 = 0. by Cramer's rule

A: Given that  By solving the equations by cramers rule

Q: Write v as a linear combination of u and w, if possible, where u = (2, 3) and w= (2, -2). (Enter…

A: We want to write v in linear combination of u and w.

Q: The points (x, -5) and (2, y) are on the line containing the points (-14, 7) and (10, 1). What is…

A: equation of line containing two points (x1,x2) and (y1,y2) is y-y1=y2-y1x2-x1x-x1

Q: The figure shows that the points (6, 12) and (8, 10) lies on a circle represented by the…

A: We will solve the following according to the given information in the question.

Q: Find the intercepts 3x-4y 12 O(0,3)(4,0) (0,-3)(4, 0) (0, 4)(3,0) O(0, 4)(-3, 0) OO O

A: Solving the problem by finding the intercept.

Q: Find the intercepts 3x-4y 12 O (0, 3)(4,0) O (0, -3)(4, 0) O (0, 4)(3, 0) O (0, 4)(-3, 0)

A: We have to find

Q: 2y3(5y3-3y2+6y)

A: It the given that, the multiplication expression,

Q: the y-intercept of (-7,-4) and (-5,-6

A: Given line passes through the points (-7,-4) and (-5,-6)

Q: A point R(3, k) lies on the straight line joining P(4, 10) and Q(1, -2). Find the value of k.

A:

Q: If the slope of one of the pairs of lines represented by equation a³x² + 2hxy + b³y² = 0 is square…

A:

Q: How would i determine whether the three points are collinear?   (0,-7), (-3,-21), (2,3)

A:

Q: Draw a picture of Cay({2, 5}:Z8).

A: Given,            Cay2, 5 : Z8.

Q: 4s+4 s2(s-2)

A:

Q: (x + 2)³ y = (x² – 4) ||

A: a2-b2 =(a-b)(a+b)

Q: RU an IF F(X )

A:

Q: Rewrite the linear equation -4(x-) = *-(7y + 3) 3x-4 in the standard form of y = mx + c

A:

Q: Evaluate ff (6x² +407) JA, where D is (0,3), (191) and (5₂3) the triangle with vertices

A:

Q: Q3/ If Ā = -3i + 2j + 5k, B = i + 2j - k and C = -i-j-2k %3D find (AXB). C

A: Let's see the concept of dot and cross product. Say xi+yj+zk and ai+bj+ck be two vectors.

Q: C is the curve y = e® from (2, e²) to (0,1) and F = (x², -y), compute ſ, F-dr.

A: Given that, C is the curve y=ex from 2,e2 to 0,1 and F=x2,-y Then, F=x2,-y=x2,-ex So, F→=x2i^-exj^

Q: What are m and b in the linear equation 5 + 6x + 4 + 2x = y?

A: Given: 5+6x+4+2x=y

Q: (A+B)2 = A2 + B2, Find x and y.

A:

Q: Plot and then label the points A(0, - 3), B(3, - 4), C(5, 6), D(- 2, - 5), and E(- 3, 5).

A: Given the pouints are A(0,-3),B(3,-4),C(5,6),D(-2,-5) and E(-3,5).

Q: Graph the points A(3, 2), B ( − 2, 1), C (3, − 4), D( − 2, − 3), E ( − 3, 0), F (0, 2),G(0, 0).

A: To plot A(3,2) we will go 3 units on x axis and 2 units on y axis.  To plot B(-2,1) we will go -2…

Q: (Dª – 6D³ +13D² – 12D+4)y = 0 |

A: