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- #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…Project Description: In this project you implement an ArrayStack ADT and use the stack for implementing the following methods: a) Reverse an array of Words: Accept an array of words as input parameter and return an array of words in reverse order. Use the method signature: public static String[] reverseWords (String[] wordList) Example Input: Bird Cat Dog Elephant Output: Elephant Dog Cat BirdProject Description: In this project you implement an ArrayStack ADT and use the stack for implementing the following methods: a) Reverse an array of Words: Accept an array of words as input parameter and return an array of words in reverse order. Use the method signature: public static String[] reverse Words (String[] wordList) Example Input: Bird Cat Dog Elephant Output: Elephant Dog Cat Bird
- class Solution(object): def longestCommonPrefix(self, strs): result ="" for i in strs[0]: for j in strs[1]: for k in strs[2]: if i == j and i == k: result+=i if len(result) >0: return result else: return result IndexError: list index out of range for j in strs[1]: Line 5 in longestCommonPrefix (Solution.py) ret = Solution().longestCommonPrefix(param_1) Line 31 in _driver (Solution.py) _driver() Line 41 in <module> (Solution.py) can someone explain why this is wrong?For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }public static int[] goodResize(int[] list, int newSize) { assert list != null && newSize >= 0 : "failed precondition"; int[] result = new int[newSize]; int limit = Math.min(list.length, newSize); for(int i = 0; i < limit; i++) { result[i] = list[i]; } return result; } **Note: Software testing & quality assurance Question: Create a control flow graph (CFG) based on the coding above and find all these paths Statement coverage Branch coverage Predicate coverage
- public static int[] goodResize(int[] list, int newSize) { assert list != null && newSize >= 0 : "failed precondition"; int[] result = new int[newSize]; int limit = Math.min(list.length, newSize); for(int i = 0; i < limit; i++) { result[i] = list[i]; } return result; } **Note: Software testing & quality assurance Question: Create a control flow graph based on the coding above and find all these paths: Statement coverage Branch coverage Predicate coverageQuestion 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews OQ1 #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
- This is a linked list node class Node { public: int data; Node *next; }; Using the above code write the following functions. Please test in the main function of your program. Please upload all code that you write. 1. Adding and removing a node 2. Removing ever third node 3. Adding the complete list at the end. if you had a list 1,2,3 the new list will be 1,2,3,1,2,3 4. Write a function to find the average of the list 5. Write a function that takes in a list as a parameter and adds it to the current list. This Node add will only happen if list 1 element is less then list 2 element. Example List 1 - 1,2,3 List 2 - 3,1,4 New List - 4,2,7 - It only adds if L2 > L1 List all assumptions.SEE MORE QUESTIONS