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Loved Solution The balance owed on your credit card triples from $800 to $2400 in 9 months. If the balance is grow linearly then it would take 34.9 months to reach $7000. If, on the other hand, the balance is growing be after 34.9 months? Round your answer to the nearest cent 800(1+0.13)* where x represents the number of months, what would the b exponentially, f(x) = f(x) In order to solve this problem, we assume the balance is growing according to the exponential functi 800(1 + 0.13)*, where the variable x represents the total number of months. Here we are interested in knowing what the balance would be after 34.9 months, so substitute 34.9 for x. = f(x) f(34.9) Correct Answer: $56,954.45 = = 800(1.13)* 90 800(1.13)34.9 ما 579 31 904 ≈56,954.45 So the balance after 34.9 months would be $56,954.45. Notice that your answer is greater than $70 Over a long period of time, exponential growth occurs at a much faster rate than linear growth. ths

Loved Solution The balance owed on your credit card triples from $800 to $2400 in 9 months. If the balance is grow linearly then it would take 34.9 months to reach $7000. If, on the other hand, the balance is growing be after 34.9 months? Round your answer to the nearest cent 800(1+0.13)* where x represents the number of months, what would the b exponentially, f(x) = f(x) In order to solve this problem, we assume the balance is growing according to the exponential functi 800(1 + 0.13)*, where the variable x represents the total number of months. Here we are interested in knowing what the balance would be after 34.9 months, so substitute 34.9 for x. = f(x) f(34.9) Correct Answer: $56,954.45 = = 800(1.13)* 90 800(1.13)34.9 ما 579 31 904 ≈56,954.45 So the balance after 34.9 months would be $56,954.45. Notice that your answer is greater than $70 Over a long period of time, exponential growth occurs at a much faster rate than linear growth. ths

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Return to Test Question 16, Step 1 of 1 loved Solution 2 caldian Dana 1 of 1 1 Hawkes Learning | Portal Correct Answer: $56,954.45 Tutor-Solution Page 1 of 1 | Hawkes Learning | Portal The balance owed on your credit card triples from $800 to $2400 in 9 months. If the balance is grow linearly then it would take 34.9 months to reach $7000. If, on the other hand, the balance is growing 800(1+0.13)* where x represents the number of months, what would the b be after 34.9 months? Round your answer to the nearest cent. exponentially, f(x) 31550 f(x) = In order to solve this problem, we assume the balance is growing according to the exponential functi 800(1 + 0.13)*, where the variable x represents the total number of months. Here we are interested in knowing what the balance would be after 34.9 months, so substitute 34.9 for x. 315496 f(x) = 800(1.13)* f(34.9) = 800(1.13) 34.2 ≈ 56,954.45 So the balance after 34.9 months would be $56,954.45. Notice that your answer is greater than $70 Over a long period of time, exponential growth occurs at a much faster rate than linear growth. IRENE months PVAT 34,9 90y goy
Transcribed Image Text:Return to Test Question 16, Step 1 of 1 loved Solution 2 caldian Dana 1 of 1 1 Hawkes Learning | Portal Correct Answer: $56,954.45 Tutor-Solution Page 1 of 1 | Hawkes Learning | Portal The balance owed on your credit card triples from $800 to $2400 in 9 months. If the balance is grow linearly then it would take 34.9 months to reach $7000. If, on the other hand, the balance is growing 800(1+0.13)* where x represents the number of months, what would the b be after 34.9 months? Round your answer to the nearest cent. exponentially, f(x) 31550 f(x) = In order to solve this problem, we assume the balance is growing according to the exponential functi 800(1 + 0.13)*, where the variable x represents the total number of months. Here we are interested in knowing what the balance would be after 34.9 months, so substitute 34.9 for x. 315496 f(x) = 800(1.13)* f(34.9) = 800(1.13) 34.2 ≈ 56,954.45 So the balance after 34.9 months would be $56,954.45. Notice that your answer is greater than $70 Over a long period of time, exponential growth occurs at a much faster rate than linear growth. IRENE months PVAT 34,9 90y goy
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