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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. рe (1- р)е 20 (1– p)eº 0.01 -0.2 (A) ре 100 10,000 100 10,000 pe (1– p)e001 10,000 Ре 100 (1– p)e02 (B) 100 10,000 (1– p)e® pe (1– p)e-02 -0.01 (C) pe¯ 100 10,000 100 10,000 pe. (1– p)e-0.01 (1– p)e02 -20 -0.2 (D) pe 100 10,000 100 10,000 e р. 100 e 0.01 |+(1- -20 e -0.2 (E) 10,000 + 100 10,000

Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1- p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. рe (1- р)е 20 (1– p)eº 0.01 -0.2 (A) ре 100 10,000 100 10,000 pe (1– p)e001 10,000 Ре 100 (1– p)e02 (B) 100 10,000 (1– p)e® pe (1– p)e-02 -0.01 (C) pe¯ 100 10,000 100 10,000 pe. (1– p)e-0.01 (1– p)e02 -20 -0.2 (D) pe 100 10,000 100 10,000 e р. 100 e 0.01 |+(1- -20 e -0.2 (E) 10,000 + 100 10,000

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1– p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. -0.01 pe (1– p)e“ pe 20 (1– p)e0² -0.2 (A) 100 10,000 100 10,000 pe (1– p)e“ -0.01 (B) pe (1– p)e02' 100 10,000 100 10,000 pe, (1- p)e0. 20 (1– p)eº -0.01 pe 100 -0.2 (C) pe 10,000 100 10,000 pe, (1- p)e 00i -0.01 (D) -20 ре (1– p)e02 100 10,000 100 10,000 e 0.01 +(1– p) e -20 (E) р. 100 10,000 100 10,000
Transcribed Image Text:Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1– p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. -0.01 pe (1– p)e“ pe 20 (1– p)e0² -0.2 (A) 100 10,000 100 10,000 pe (1– p)e“ -0.01 (B) pe (1– p)e02' 100 10,000 100 10,000 pe, (1- p)e0. 20 (1– p)eº -0.01 pe 100 -0.2 (C) pe 10,000 100 10,000 pe, (1- p)e 00i -0.01 (D) -20 ре (1– p)e02 100 10,000 100 10,000 e 0.01 +(1– p) e -20 (E) р. 100 10,000 100 10,000
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