Looking at the table below what do you conclude in a test of weekly expenditure on fruit between females and non-females if one were testing the null hypothesis of no difference against a 1-sidedalternative that females spend more on fruit at the 5% significance level:Two-sample t test with equal variancesGroup Obs Mean Std. err. Std. dev. [95% conf. interval]Female 377 14.661 .4317 8.381 13.812 15.510Non-Female 206 13.801 .5113 7.339 12.793 14.809Combined 583 14.357 .6956 8.033 13.703 15.011diff.8602 .6957-.5061 2.2265diff= mean(Female) - mean(Non-Female)HO: diff = 0Ha: diff < 0Pr(Tt) = 0.892Ha: diff != 0Pr(|T| > |t|) = 0.217With a p-value of 0.892 we do not reject HOWith a p-value of 0.892 we accept HOWith a p-value of 0.108 we do not reject HOWith a p-value of 0.217 we do not reject HOt = 1.237Degrees of freedom = 581Ha: diff > 0Pr(T>t) = 0.108

Given hypothesis: Testing the null hypothesis of no difference against a 1-sided alternative that…

Answered: Looking at the table below what do you…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

Under what conditions should you use the pooled-variance t test to examine possible differences in the means of two independent populations?
A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses per month was based on random samples and yielded the following results: n1 = 40 ¯x1 = 9.1 s1 = 1.9 n2 = 50 ¯x2 = 8.0 s2 = 2.1. Test the hypothesis that there is no difference between the averages at 5% significance level.
Consider the ANOVA table shown here for a one-way analysis of variance for an experimental design in which there are four treatment levels: Source Between Error Total Df 29 SS 485.50 715.50 The observed F value is ____. MS F
A two-sample hypothesis test is comparing the averages of the following populations. Population 1 is the salary of female employees and Population 2 is the salary of male employees. A hypothesis test was conducted to see if the average salary of males is greater than the average salary of females. Using the following as the output of the test, state the P-value and interpret the results in context to the problem. Use a significance level of 5% Mean Variance Observations Hypothesized Mean Difference df t Stat P(T<=t) one-tail t Critical one-tail P(T<=t) two-tail t Critical two-tail Females Males 65,852.00 89,562.00 1,003.00 1,025.00 45 30 0 37 -1.26 0.1200 1.3300 0.2400 1.2800 For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial 10pt EEVA V Tx XQ5 二三 ||||| WORDS POWERED BY TINY
(a) Perform the analysis of variance (ANOVA) at the 5% significance level to identify is there any difference in the mean between the three populations. 1 2 3 94 71 84 96 82 87 87 87 93 89
When three groups were compared using the one-way Analysis of Variance (ANOVA), the result turned out to be significant, that is, the null hypothesis was rejected. What will be the appropriate interpretation of this result?A. All three groups significantly differ in means.B. Exactly two of the three groups significantly differ.C. At least two of the three groups significantly differ in means.D. All three groups have the same effect on the dependent variable.
A researcher was interested in knowing if mean BMI was different between males and females. He obtained the following test results. Choose the correct interpretation of the results: F test p value = 0.03 Two sample t test, assume equal variance = 0.02 Two sample t test, assume unequal variance = 0.06 Mean BMI is higher in males than females. None Mean BMI is not significantly different between males and females. Mean BMI is significantly different between males and females.
A researcher was interested in knowing if mean BMI was different between males and females. He obtained the following test results. Choose the correct interpretation of the results: F test p value = 0.30 Two sample t test, assume equal variance = 0.02 Two sample t test, assume unequal variance = 0.61 Mean BMI is not significantly different between males and females. None Mean BMI is higher in males than females. Mean BMI is significantly different between males and females.
Do cars really get better mileage per gallon on the highway? The table shows results from a study of the MPG (miles per gallon) of cars both in the city and on the highway. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. At the 0.1 significance level, test the claim that the mpg on the highway is better than in the city. MPG on the Highway 35.6 34.3 32.2 33.9 31.1 27.1 33.3 33.4 29.3 33.5 31.4 33.2 33.5 30.8 33.8 MPG in the City 26.4 25.3 18.6 25.6 24.7 24.6 25.1 22.4 29.3 23.7 23.4 22 24 23.6 25.5 What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer p x̄₁ p₁ σ₁² μ₁ μ₂ μ μ(Highway) x̄₂ p̂₁ s₁² p₂ ? ≤ ≠ < ≥ = > Select an answer p₁ p₂ p̂₁ μ(City) μ μ₁ μ₂ x̄₁ x̄₂ s₁² σ₁² p H1: Select an answer p₂ μ(Highway) p̂₂ σ₂² x̄₁ x̄₂ s₂² μ₁ μ₂ μ p₁ p ? < ≠ = ≥ ≤ > Select an answer p₂ p₁ μ₁ σ₁²…
Given below are the analysis of variance results from a stat software display comparing sample data for the meanmileage for 4 different types of cars. Assume that you want to use a 0.05 significance level in testing the null hypothesisthat the different samples come from cars with the same mileage. What can you conclude about the equality of the population means?Source DF SS MS F pFactor 3 13.500 4.500 5.17 0.011Error 16 13.925 0.870Total 19 27.425 12)What is the null and alternative hypothesis for this scenari?Based on this One Way Anova software analysis, would you reject of fail to reject the nul hypothesis?What does this result mean in context?

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