Long term testing of concrete shows that the mean strength (u) is 3500 psi with a standard deviation (o) of 400 psi. (a) Assuming a normal distribution, use the standard normal table provided to find the probability P(x) that concrete strength is at least 3000 psi. P(x ≥ 3000) = Z = X - H 050 b) If 25 samples of concrete are tested, find the probability P(x) that the sample mean is at least 3540 psi.

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4.
Long term testing of concrete shows that the mean strength (u) is 3500 psi with a standard
deviation (o) of 400 psi.
(a) Assuming a normal distribution, use the standard normal table provided to find
the probability P(x) that concrete strength is at least 3000 psi.
Z = X - μ
O
3x)²), (c) + (22 / 3y)²), (6₂³)
P(x ≥ 3000)
(b) If 25 samples of concrete are tested, find the probability P(x) that the sample mean is
at least 3540 psi.
Z =
√n (x-µ)
O
P(x ≥ 3540) =
Transcribed Image Text:4. Long term testing of concrete shows that the mean strength (u) is 3500 psi with a standard deviation (o) of 400 psi. (a) Assuming a normal distribution, use the standard normal table provided to find the probability P(x) that concrete strength is at least 3000 psi. Z = X - μ O 3x)²), (c) + (22 / 3y)²), (6₂³) P(x ≥ 3000) (b) If 25 samples of concrete are tested, find the probability P(x) that the sample mean is at least 3540 psi. Z = √n (x-µ) O P(x ≥ 3540) =
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