Lombard Electronics Company has just installed a new machine that makes a part that isused in clocks. The company wants to estimate the proportion of these parts produced bythis machine that are defective. The company manager wants this estimate to be within .02of the population proportion for a 95% confidence level. What is the most conservative es-timate of the sample size that will limit the margin of error to within .02 of the populationproportion?

Answered: Image /qna-images/answer/f392793d-8fb0-4c35-b8dd-1c97a4a3a951.jpg

Answered: Lombard Electronics Company has just…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The variance in drug weighs is critical in the pharmaceutical industry. For specific drug, with weights measured in grams, a sample of 18 units provided a sample variance =0.36. A. Construct a 90% confidence interval estimate of the population variance for the weight of this drug. B. Construct a 90% confidence interval estimate of the population standard deviation. use excel please
9. What sample size is needed to give a margin of error of 2.5% with a 95% confidence level?
among various ethnic groups, the standard deviation of heights is known to be approximately three inches. We wish to construct a 95% confidence interval for the mean height of males from a certain country. Forty eight males are surveyed from a particular country.. The sample mean is 70 inches. The sample standard deviation is 2.6 inches. construct a 95% confidence interval for the population mean height of males of theis country?
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained physical activity. What sample size should be obtained if she wishes the estimate to be within five percentage points with 95% confidence, assuming that (a) she uses the estimates of 22.9% male and 19.5% female from a previous year? (b) she does not use any prior estimates?
You want to estimate the mean weight of quarters in circulation. A sample of 60 quarters has a mean weight of 5.682 grams and a standard deviation of 0.061 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) grams. Find the 95% confidence interval for the mean weight of all quarters. grams < p< grams (Round to three decimal places as needed.)
The Nero Match Company sells matchboxes that are supposed to have an average of 40 matches per box, with ? = 8. A random sample of 90 matchboxes shows the average number of matches per box to be 43.0. Using a 1% level of significance, can you say that the average number of matches per box is more than 40?What are we testing in this problem? single meansingle proportion (a) What is the level of significance?State the null and alternate hypotheses. H0: p = 40; H1: p > 40H0: p = 40; H1: p ≠ 40 H0: p = 40; H1: p < 40H0: ? = 40; H1: ? > 40H0: ? = 40; H1: ? ≠ 40H0: ? = 40; H1: ? < 40 (b) What sampling distribution will you use? What assumptions are you making? The Student's t, since we assume that x has a normal distribution with known ?.The standard normal, since we assume that x has a normal distribution with known ?. The standard normal, since we assume that x has a normal distribution with unknown ?.The Student's t, since we assume that x has a normal distribution…
If a sample of 25 fish from my pond has mean weight 157 grams with a standard deviation of 8.3 grams and we know the population standard deviation for the fish in my pond is actually 9.4 grams, then WHAT IS the MARGIN OF ERROR in the 99 percent confidence interval for true mean weight of fish in my pond? Group of answer choices
A football coach claims that the average weight of all opposing teams’ members is 225 pounds. For a test of the claim, a simple random sample of 50 players is taken from all the opposing teams. The mean is found to be 230 pounds with a standard of 15 pounds. Construct a 95% confidence interval for the unknown average weight of the population of all the players of opposing teams. Interpret your result.
What is the approximate sample size required to estimate the percentage of Americans who have earned a college degree to within 2%, with 95% confidence?
The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14). State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why? 22.95 is in the center of the interval. The means are definitely not different. 22.95 is just outside the 95% confidence interval. Can't say the means are really different. 22.95 is not equal to 20.7. The means are definitely different. 20.7 is just outside the 95% confidence interval. Can't say the means are really different.
12. A new manufacturing process of component parts is being considered. Samples were taken improves the proportion of defective components. 1425 of 1500 components from the existing process and 1920 of 2000 components from the new process were found to be non-defective. 75 80 P1 = = 0.05, P2 = 0.04 and Pi - P2 = 0.05 - 0.04 = 0.01 1500 2000 a. Find a 99% confidence interval for the true difference in the fraction of defectives between the existing and the new processes? b. Based on your answer in (a), is there any significant difference between the existing and the new processes? Justify?
2. There was a sample of 14 adult wild mountain lions who were caught and released in the San Andres Mountains. The average weight of the sample was 82.55 pounds with a sample standard deviation of 13.45 pounds. Find a 95% confidence interval for the population mean weight of all the wild mountain lions in the San Andres Mountains.

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