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log. ) 1) The conversion between exponential form and logarithmic form: Logarithmic form Exponential form log; 125 53 = 125 log a = y ek = m Inc= 17 49-1/2 = 7 2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions: Law of Logarithms: log. (AB) = log, A+ log, B, loga log, A – log, B, log. (AC) = C - log, В. a) Expand log(AB²C®) b) Combine log, x + log, (x + 1)

log. ) 1) The conversion between exponential form and logarithmic form: Logarithmic form Exponential form log; 125 53 = 125 log a = y ek = m Inc= 17 49-1/2 = 7 2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions: Law of Logarithms: log. (AB) = log, A+ log, B, loga log, A – log, B, log. (AC) = C - log, В. a) Expand log(AB²C®) b) Combine log, x + log, (x + 1)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1) The conversion between exponential form and logarithmic form: Logarithmic form Exponential form log, 125 53 = 125 log æ = y ek = In c = 17 49-1/2 7 2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions: Law of Logarithms: log. (AB) = log, A + log, B, loga = loga A – loga B, log. (AC) = C · log, - B a) Expand log(AB²C³) b) Combine log, r + log2 (x + 1)
Transcribed Image Text:1) The conversion between exponential form and logarithmic form: Logarithmic form Exponential form log, 125 53 = 125 log æ = y ek = In c = 17 49-1/2 7 2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions: Law of Logarithms: log. (AB) = log, A + log, B, loga = loga A – loga B, log. (AC) = C · log, - B a) Expand log(AB²C³) b) Combine log, r + log2 (x + 1)
1 1 as 5'. Then use it to solve the equation 54-* 125 1) Rewrite 125 2) Rewrite e2" as (??)². Then use it to solve the equation e2 – e – 6 = 0 3) Rewrite 2 as a logarithmic of base 3. That means 2 = log3 log3 (x – 8) + log3 x. Now solve the equation log3 (x – 8) + log; a = 2. After you solve the Then combine equation, make sure you substitute your answer back so that the value under log is not negative.
Transcribed Image Text:1 1 as 5'. Then use it to solve the equation 54-* 125 1) Rewrite 125 2) Rewrite e2" as (??)². Then use it to solve the equation e2 – e – 6 = 0 3) Rewrite 2 as a logarithmic of base 3. That means 2 = log3 log3 (x – 8) + log3 x. Now solve the equation log3 (x – 8) + log; a = 2. After you solve the Then combine equation, make sure you substitute your answer back so that the value under log is not negative.
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