log. ) 1) The conversion between exponential form and logarithmic form: Logarithmic form Exponential form log; 125 53 = 125 log a = y ek = m Inc= 17 49-1/2 = 7 2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions: Law of Logarithms: log. (AB) = log, A+ log, B, loga log, A – log, B, log. (AC) = C - log, В. a) Expand log(AB²C®) b) Combine log, x + log, (x + 1)
log. ) 1) The conversion between exponential form and logarithmic form: Logarithmic form Exponential form log; 125 53 = 125 log a = y ek = m Inc= 17 49-1/2 = 7 2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions: Law of Logarithms: log. (AB) = log, A+ log, B, loga log, A – log, B, log. (AC) = C - log, В. a) Expand log(AB²C®) b) Combine log, x + log, (x + 1)
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter11: Exponential And Logarithmic Functions
Section11.CR: Review Problem Set
Problem 34CR
Related questions
Question
![1) The conversion between exponential form and logarithmic form:
Logarithmic form Exponential form
log, 125
53 = 125
log æ = y
ek =
In c = 17
49-1/2
7
2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions:
Law of Logarithms:
log. (AB) = log, A + log, B,
loga
= loga A – loga B,
log. (AC) = C · log, -
B
a) Expand log(AB²C³)
b) Combine log, r + log2 (x + 1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe2257a7-ec8b-4cb2-8972-c13e17aa7768%2F95790fef-ea79-4e18-b81f-91fa986e662e%2Ffr7t7bg_processed.png&w=3840&q=75)
Transcribed Image Text:1) The conversion between exponential form and logarithmic form:
Logarithmic form Exponential form
log, 125
53 = 125
log æ = y
ek =
In c = 17
49-1/2
7
2) Properties/Laws of Logarithms: Use the following laws of logarithms to answer the questions:
Law of Logarithms:
log. (AB) = log, A + log, B,
loga
= loga A – loga B,
log. (AC) = C · log, -
B
a) Expand log(AB²C³)
b) Combine log, r + log2 (x + 1)
![1
1
as 5'. Then use it to solve the equation 54-*
125
1) Rewrite
125
2) Rewrite e2" as (??)². Then use it to solve the equation e2 – e – 6 = 0
3) Rewrite 2 as a logarithmic of base 3. That means 2 = log3
log3 (x – 8) + log3 x. Now solve the equation log3 (x – 8) + log; a = 2. After you solve the
Then combine
equation, make sure you substitute your answer back so that the value under log is not negative.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe2257a7-ec8b-4cb2-8972-c13e17aa7768%2F95790fef-ea79-4e18-b81f-91fa986e662e%2Fo0belx_processed.png&w=3840&q=75)
Transcribed Image Text:1
1
as 5'. Then use it to solve the equation 54-*
125
1) Rewrite
125
2) Rewrite e2" as (??)². Then use it to solve the equation e2 – e – 6 = 0
3) Rewrite 2 as a logarithmic of base 3. That means 2 = log3
log3 (x – 8) + log3 x. Now solve the equation log3 (x – 8) + log; a = 2. After you solve the
Then combine
equation, make sure you substitute your answer back so that the value under log is not negative.
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