log y Solve 5*-* = 7 for x using the change of base formula log, y- log b O 5.209 O 4.827 O-2.791

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Logarithmic Equation Solving Example**

*Objective: Solve for \( x \) in the equation \( 6^{x-4} = 7 \) using the change of base formula.*

### Problem Statement:
Solve \( 6^{x-4} = 7 \) for \( x \) using the change of base formula:
\[ \log_b y = \frac{\log y}{\log b} \]

### Answer Choices:
- \( \) 5.209
- \( \) 4.827
- \( \) -2.791
- \( \) -3.173

### Solution Steps:
1. Start with the equation:\[ 6^{x-4} = 7 \]
2. Apply the natural logarithm (or common logarithm) to both sides:
\[ \log (6^{x-4}) = \log 7 \]
3. Use the logarithm power rule (\( \log a^b = b \log a \)):
\[ (x-4) \log 6 = \log 7 \]
4. Solve for \( x-4 \) by isolating the variable on one side:
\[ x-4 = \frac{\log 7}{\log 6} \]
5. Finally, solve for \( x \):
\[ x = 4 + \frac{\log 7}{\log 6} \]

### Verify the Answer
Now substitute each answer choice into the solution to find the correct value:
1. **\( x = 5.209 \)**: 
\[ 5.209 - 4 = 1.209 \]
\[ 6^{1.209} \approx 7 \] (Approximately true, calculated value close to 7)
2. **\( x = 4.827 \)**: 
\[ 4.827 - 4 = 0.827 \]
\[ 6^{0.827} \not\approx 7 \] (Approximately not true, calculated value not close to 7)
3. **\( x = -2.791 \)**: 
\[ -2.791 - 4 = -6.791 \]
\[ 6^{-6.791} \not\approx 7 \] (Approximately not true, calculated value not close to 7)
4. **\( x = -3.173 \)**: 
\[ -
Transcribed Image Text:**Logarithmic Equation Solving Example** *Objective: Solve for \( x \) in the equation \( 6^{x-4} = 7 \) using the change of base formula.* ### Problem Statement: Solve \( 6^{x-4} = 7 \) for \( x \) using the change of base formula: \[ \log_b y = \frac{\log y}{\log b} \] ### Answer Choices: - \( \) 5.209 - \( \) 4.827 - \( \) -2.791 - \( \) -3.173 ### Solution Steps: 1. Start with the equation:\[ 6^{x-4} = 7 \] 2. Apply the natural logarithm (or common logarithm) to both sides: \[ \log (6^{x-4}) = \log 7 \] 3. Use the logarithm power rule (\( \log a^b = b \log a \)): \[ (x-4) \log 6 = \log 7 \] 4. Solve for \( x-4 \) by isolating the variable on one side: \[ x-4 = \frac{\log 7}{\log 6} \] 5. Finally, solve for \( x \): \[ x = 4 + \frac{\log 7}{\log 6} \] ### Verify the Answer Now substitute each answer choice into the solution to find the correct value: 1. **\( x = 5.209 \)**: \[ 5.209 - 4 = 1.209 \] \[ 6^{1.209} \approx 7 \] (Approximately true, calculated value close to 7) 2. **\( x = 4.827 \)**: \[ 4.827 - 4 = 0.827 \] \[ 6^{0.827} \not\approx 7 \] (Approximately not true, calculated value not close to 7) 3. **\( x = -2.791 \)**: \[ -2.791 - 4 = -6.791 \] \[ 6^{-6.791} \not\approx 7 \] (Approximately not true, calculated value not close to 7) 4. **\( x = -3.173 \)**: \[ -
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