lOF3 is a powerful fluorinating and oxidizing agent. It can be made by fluorination of Cl2O: Cl2O + 2F2 ClOF3 + ClF Assign an oxidation number to each atom and verify that the total number of electrons lost is equal to the total number gained. Enter the oxidation numbers under each substance in the box corresponding to the element label to the left.
lOF3 is a powerful fluorinating and oxidizing agent. It can be made by fluorination of Cl2O: Cl2O + 2F2 ClOF3 + ClF Assign an oxidation number to each atom and verify that the total number of electrons lost is equal to the total number gained. Enter the oxidation numbers under each substance in the box corresponding to the element label to the left.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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ClOF3 is a powerful fluorinating and oxidizing agent. It can be made by fluorination of Cl2O:
Assign an oxidation number to each atom and verify that the total number of electrons lost is equal to the total number gained.
For the reaction as written, the total number of electrons lost is and the total number of electrons gained is .
Cl2O | + | 2F2 | ClOF3 | + | ClF |
Assign an oxidation number to each atom and verify that the total number of electrons lost is equal to the total number gained.
- Enter the oxidation numbers under each substance in the box corresponding to the element label to the left.
- If a box is not needed, leave it blank.
Cl2O | F2 | ClOF3 | ClF | ||||
Cl | |||||||
O | |||||||
F |
For the reaction as written, the total number of electrons lost is and the total number of electrons gained is .
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