lodine exists as molecules of 12, and silicon dioxide exists as an extended network of silicon-oxygen bonds (similar to diamond). They both are solids at room temperature, but which do you think has the higher melting point and why? A. Silicon dioxide because to melt it you would have to break covalent bonds. B. 1₂ because it is heavier and therefore has the largest LDFs. C. 12 because it an element. D. Silicon dioxide, because it is a compound and has stronger intermolecular forces than iodine molecules. OD OA OB OC

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lodine exists as molecules of 12, and silicon dioxide exists as an extended network of silicon-oxygen bonds (similar to diamond). They both are solids at room temperature, but which do you
think has the higher melting point and why?
A. Silicon dioxide because to melt it you would have to break covalent bonds.
B. 1₂ because it is heavier and therefore has the largest LDFs.
C. 1₂ because it an element.
D. Silicon dioxide, because it is a compound and has stronger intermolecular forces than iodine molecules.
OD
O A
OB
OC
Transcribed Image Text:lodine exists as molecules of 12, and silicon dioxide exists as an extended network of silicon-oxygen bonds (similar to diamond). They both are solids at room temperature, but which do you think has the higher melting point and why? A. Silicon dioxide because to melt it you would have to break covalent bonds. B. 1₂ because it is heavier and therefore has the largest LDFs. C. 1₂ because it an element. D. Silicon dioxide, because it is a compound and has stronger intermolecular forces than iodine molecules. OD O A OB OC
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