locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b dx then a at t=0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V = dt 7.5 t = V da dt 7.5(1 – 0.04 x)0.3 T √₁² (₁1-0 (10.04 x) 0.3 dx S (1 - 0.04 x) 0.71* 250 (0.7)(-0.04) Jo 7 TRABAN 7.5 dt [1 − (1 – 0.04 x) ⁰.7] 0.21 t= (1-(10.04 a)0.7)
locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b dx then a at t=0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V = dt 7.5 t = V da dt 7.5(1 – 0.04 x)0.3 T √₁² (₁1-0 (10.04 x) 0.3 dx S (1 - 0.04 x) 0.71* 250 (0.7)(-0.04) Jo 7 TRABAN 7.5 dt [1 − (1 – 0.04 x) ⁰.7] 0.21 t= (1-(10.04 a)0.7)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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i dont undertsand those steps could you explain them to me please what do they do on each step
![locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b
dr
then a
at t-0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V
dt
7.5 t=
... VE =
147
Kis
JO
dar
dt
= 7.5(1 – 0.04 x) 0.3
(1 – 0.04 z
0.04 x) 0.3 dx
(10.04 x) 0.71*
77-
(0.7)(-0.04)
10
||
250
7
S
1
7.5 dt
(1-0.04 z)07]
x)⁰.7]
0.21 t = (1 – (1 – 0.04 x)0.7)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7dcea35-5347-4af5-9461-3cfff5fd7ee7%2F12f46736-0d7d-4c77-845e-cb8e1e9cfefb%2Fo9uv4c8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b
dr
then a
at t-0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V
dt
7.5 t=
... VE =
147
Kis
JO
dar
dt
= 7.5(1 – 0.04 x) 0.3
(1 – 0.04 z
0.04 x) 0.3 dx
(10.04 x) 0.71*
77-
(0.7)(-0.04)
10
||
250
7
S
1
7.5 dt
(1-0.04 z)07]
x)⁰.7]
0.21 t = (1 – (1 – 0.04 x)0.7)
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