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locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b dx then a at t=0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V = dt 7.5 t = V da dt 7.5(1 – 0.04 x)0.3 T √₁² (₁1-0 (10.04 x) 0.3 dx S (1 - 0.04 x) 0.71* 250 (0.7)(-0.04) Jo 7 TRABAN 7.5 dt [1 − (1 – 0.04 x) ⁰.7] 0.21 t= (1-(10.04 a)0.7)

locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b dx then a at t=0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V = dt 7.5 t = V da dt 7.5(1 – 0.04 x)0.3 T √₁² (₁1-0 (10.04 x) 0.3 dx S (1 - 0.04 x) 0.71* 250 (0.7)(-0.04) Jo 7 TRABAN 7.5 dt [1 − (1 – 0.04 x) ⁰.7] 0.21 t= (1-(10.04 a)0.7)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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i dont undertsand those steps could you explain them to me please what do they do on each step

locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b dr then a at t-0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V dt 7.5 t= ... VE = 147 Kis JO dar dt = 7.5(1 – 0.04 x) 0.3 (1 – 0.04 z 0.04 x) 0.3 dx (10.04 x) 0.71* 77- (0.7)(-0.04) 10 || 250 7 S 1 7.5 dt (1-0.04 z)07] x)⁰.7] 0.21 t = (1 – (1 – 0.04 x)0.7)
Transcribed Image Text:locity is given as a function of position, and we need to determine (a) the position at t-1 h, (b dr then a at t-0, and (c) the time at x-6 mi, so we will use the basic kinematic relation V dt 7.5 t= ... VE = 147 Kis JO dar dt = 7.5(1 – 0.04 x) 0.3 (1 – 0.04 z 0.04 x) 0.3 dx (10.04 x) 0.71* 77- (0.7)(-0.04) 10 || 250 7 S 1 7.5 dt (1-0.04 z)07] x)⁰.7] 0.21 t = (1 – (1 – 0.04 x)0.7)
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