Locate the absolute extrema of the function on the closed interval. f(x)= x³ 12x, [0, 4] -

Q: Find where the function is increasing. 2 y = x² - 3lnx, (x > 0)

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Q: DERIVE THE FF. FUNCTIONS: y.x(x-) 4x²+ 3x+2 %3D t.

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Q: 5- -4 -5 -4 -2 -3 -5 -5 0 -5 -4 -3 -2 2. ent

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Q: Give the domain of the function  y = x2/3. as interval notation

A: Given : y = x2/3  To find : Domain of the given function.

Q: Find and sketch the domain for the function. f(x.y) = / (x² - 16) (y² -9)

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Q: Draw the function of y = x 2 / 3 + x2

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Q: Where does the original function f(x) increases and decreased

A: f'(x) = +ve→f(x) will be increasing in this range.f'(x) = -ve→f(x) will be decreasing in this…

Q: nd the slope of the graph of the function f(x) - X X- 2 at x = 0.

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Q: Differentiate the function. f(x) = 16{x – 3 +2x

A: Given   f(x) = 16 x4-3+2x     now differentiating 1 w.r.t. 'x ' , we get    f'(x) = ddx16x14-3+2x…

Q: Consider the function f(x)=2x* – 4x² +4. Isƒincreasing or decreasing at the point x - 0.5?

A: Since you have asked multiple questions in a single request, we would be answering only first…

Q: Use the formula to express h as a function of x if h = 3y-2/4y and y= x-4

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