Locate the absolute extrema of the function on the closed interval. 3 5-8 [-6, -3] h(s) = minimum (s, h)=(-6,-0.21 maximum (s, h) = (-3,-0.27 Additional Materials X) X )

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Locate the absolute extrema of the function on the closed interval.
h(s) = 5-8' [-6, -3)
minimum (s, h)= (-6,-0.21
maximum
(s, h)=(-3,-0.27
Additional Materials
Matth
x)
X)
Transcribed Image Text:Locate the absolute extrema of the function on the closed interval. h(s) = 5-8' [-6, -3) minimum (s, h)= (-6,-0.21 maximum (s, h)=(-3,-0.27 Additional Materials Matth x) X)
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