load scenario A cut 3.92 N -Y 140mm * D'Y RA 300mm shear force. SFul-3.92+5.9493. SFeut-1.8293 N IRB → load sse ri R. As length of beam 440 (140+300) cut 4 point B at end & collapse Taking moment about B EMB=0 -3.92 (440) + RA (300) = 0 RA= 5.7493 N. Z Fy = 0. RA+RB- 3.92. A RB 18293 =
load scenario A cut 3.92 N -Y 140mm * D'Y RA 300mm shear force. SFul-3.92+5.9493. SFeut-1.8293 N IRB → load sse ri R. As length of beam 440 (140+300) cut 4 point B at end & collapse Taking moment about B EMB=0 -3.92 (440) + RA (300) = 0 RA= 5.7493 N. Z Fy = 0. RA+RB- 3.92. A RB 18293 =
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.2.4P: Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.
Related questions
Question
Draw the shear force diagrams. For each of the diagram, use the full span of the beam and not the cut position
![load scenario A
cul
3.92 N
-AY
140mm
* D'Y
Tom
RA
shear force.
SFul-3.92+5.9493.
SFut-1.8293 N
RRA
300mm
load scenario B.
cut
RA
196N 3.92
220mm 1
260min
300mm
load scenario D
cut
IRB
240mm
43/N 392
400mm
300mm
RB
RB
As length of beam 440
(140+300)
cut 4 point B at end & collapse
Taking moment about B
EMB=0
-3.92 (440) + RA (300) = 0
RA= 5.7493 N.
Z Fy = 0.
RA+RB - 3.92.
RB 18293
2
Reactions
ΣΜΑΞΟ
-RB (440) + 3-92 (260) +1.96 (220)=6
RB 3.2963 N.
shear force
SFcut = RB -
SFcut
=
3.2963 N'
Reacrons
EMA
RB (446) + 392 (400) + 4.91 (240)=0
RB = 6-2418 N.
- shear force.
SFcut
SFcut
= 6.2418- 3.92.
2.32. N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabdd1821-d7b6-4171-a67e-edf70418727b%2F6e23f243-1dbc-46f5-9a35-51f1f08f23eb%2Fhxi0ntc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:load scenario A
cul
3.92 N
-AY
140mm
* D'Y
Tom
RA
shear force.
SFul-3.92+5.9493.
SFut-1.8293 N
RRA
300mm
load scenario B.
cut
RA
196N 3.92
220mm 1
260min
300mm
load scenario D
cut
IRB
240mm
43/N 392
400mm
300mm
RB
RB
As length of beam 440
(140+300)
cut 4 point B at end & collapse
Taking moment about B
EMB=0
-3.92 (440) + RA (300) = 0
RA= 5.7493 N.
Z Fy = 0.
RA+RB - 3.92.
RB 18293
2
Reactions
ΣΜΑΞΟ
-RB (440) + 3-92 (260) +1.96 (220)=6
RB 3.2963 N.
shear force
SFcut = RB -
SFcut
=
3.2963 N'
Reacrons
EMA
RB (446) + 392 (400) + 4.91 (240)=0
RB = 6-2418 N.
- shear force.
SFcut
SFcut
= 6.2418- 3.92.
2.32. N
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