ListQueue Node Node Node front = next next next - null data - "Jones" rear = data "Thome" data - "Abreu" size 3 The above is a queue of a waiting list. The ListQueue has a node (front) to record the address of the front element of a queue. It also has another node (rear) to record the address of the tail element of a queue. 4. How do you push a node with data, "Chu" to the above queue? a. front.next = new Node("Chu", front); b. front = new Node ("Chu", front) rear = new Node ("Chu", rear) с. %3D d. rear = new Node("Chu", rear.next) Describe the reason of your choice. Your answer is (a, b, c, or d) Will the push action take time in 0(1) or 0(n)?
ListQueue Node Node Node front = next next next - null data - "Jones" rear = data "Thome" data - "Abreu" size 3 The above is a queue of a waiting list. The ListQueue has a node (front) to record the address of the front element of a queue. It also has another node (rear) to record the address of the tail element of a queue. 4. How do you push a node with data, "Chu" to the above queue? a. front.next = new Node("Chu", front); b. front = new Node ("Chu", front) rear = new Node ("Chu", rear) с. %3D d. rear = new Node("Chu", rear.next) Describe the reason of your choice. Your answer is (a, b, c, or d) Will the push action take time in 0(1) or 0(n)?
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:ListQueue
Node
Node
Node
front=
next
next=
next = nul1
rear =
data "Thome"
data "Abreu"
data - "Jones"
size - 3
The above is a queue of a waiting list. The ListQueue has a node (front)
to record the address of the front element of a queue. It also has another
node (rear) to record the address of the tail element of a queue.
4. How do you push a node with data, "Chu" to the above queue?
front.next = new Node("Chu", front);
a.
b.
front = new Node ("Chu", front)
rear = new Node("Chu", rear)
с.
d.
= new Node ("Chu", rear.next)
rear
Describe the reason of your choice.
Your answer is
(a, b, c, or d)
Will the push action take time in 0(1) or 0(n)?
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