The regression equation is correct ...help me solve the second question and the answer is NOT 66.1...is there a way I could do the second part on a ti84 plus ### Systolic Blood Pressure AnalysisListed below are systolic blood pressure measurements (in mm Hg) obtained from the same woman. These measurements are taken from both the right arm and the left arm. The objective is to find the regression equation, letting the right arm blood pressure be the predictor (x) variable. We will then use the regression equation to find the best predicted systolic blood pressure in the left arm, given that the systolic blood pressure in the right arm is 95 mm Hg. The significance level is set at 0.05.**Measurements:**| Arm | Trial 1 | Trial 2 | Trial 3 | Trial 4 | Trial 5 ||---------|---------|---------|---------|---------|---------|| Right Arm | 103 | 102 | 94 | 76 | 75 || Left Arm | 177 | 172 | 145 | 145 | 144 |*Please click the icon to view the critical values of the Pearson correlation coefficient r.*#### Regression EquationThe regression equation is given by:\[ \hat{y} = 66 + 1.0x \]*Note: The equation is rounded to one decimal place as needed.*#### PredictionGiven that the systolic blood pressure in the right arm is 95 mm Hg, the best predicted systolic blood pressure in the left arm is:\[ \hat{y} = \boxed{161} \]*Note: The prediction is rounded to one decimal place as needed.*This analysis helps in understanding the relationship between systolic blood pressure measurements taken from different arms and how one can predict the other using regression analysis.

Given: sample size n = 5 Formula Used: The regression equation: Y = a + bX b = n∑XY-∑X∑Yn∑X2-∑X2 a =…

Listed below are systolic blood pressure measurements (in mm Hg) obtained from the same woman. Find the regression equation, letting the right arm blood pressure be the predictor (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 95 mm Hg. Use a significance level of 0.05. Right Arm 102 76 103 177 94 145 Left Arm 172 145 Click the icon to view the critical values of the Pearson correlation coefficient r 75 144 The regression equation is y= 66+ 1.0 x (Round to one decimal place as needed.) C Given that the systolic blood pressure in the right arm is 95 mm Hg, the best predicted systolic blood pressure in the left arm is (Round to one decimal place as needed.) mm Hg.

Listed below are systolic blood pressure measurements (in mm Hg) obtained from the same woman. Find the regression equation, letting the right arm blood pressure be the predictor (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 95 mm Hg. Use a significance level of 0.05. Right Arm 102 76 103 177 94 145 Left Arm 172 145 Click the icon to view the critical values of the Pearson correlation coefficient r 75 144 The regression equation is y= 66+ 1.0 x (Round to one decimal place as needed.) C Given that the systolic blood pressure in the right arm is 95 mm Hg, the best predicted systolic blood pressure in the left arm is (Round to one decimal place as needed.) mm Hg.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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