Listed below are prices in dollars for one night at different hotels in a certain region. Find the range, variance, and standard deviation for the given sample data. Include appropriate units in the results. How usefuare the measures of variation for someone searching for a room?175156123The range of the sample data is(Round to one decimal place as needed.)The standard deviation of the sample data is(Round to one decimal place as needed.)The variance of the sample data is(Round to one decimal place as needed.)How useful are the measures of variation for someone searching for a room?234C206270194114O A. The measures of variation are very useful because a person does not want to buy a room where the variation is too low.O B. The measures of variation are not very useful because the values are nominal data that do not measure or count anything, so the resulting statistics are meaningless.O C. The measures of variation are very useful because a person does not want to buy a room where the variation is too high.O D. The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

The given data is as follows:175, 156, 123, 234, 206, 270, 194, 114

Answered: Listed below are prices in dollars for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The scores and their percent of the final grade for a statistics student are given. What is the student's weighted mean score? The student's weighted mean score is. (Simplify your answer. Round to two decimal places as needed.) Homework Quiz Quiz Project Final Exam Score Percent of final grade 85 90 90 98 89 15 10 10 35 30
A population has a mean p= 79 and a standard deviation o = 12. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 36. %3D H=(Simplify your answer.) %3D (Simplify your answer)
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 58.1 degrees. Which of the following best describes the relationship between the computed mean and the actual mean? Low Temperature (◦F) 40−44 45−49 50−54 55−59 60−64 Frequency 2 6 11 6 3
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). E Click the icon to view the data. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 H,: Ha #0 O B. Ho: Ha #0 H1: Hd =0 O C. Ho: Ha #0 O D. Ho: Ha = 0 H1: Hd 0
Find the range, the standard deviation, and the variance for the given samples. Round non-integer results to the nearest tenth. 74, 47, 85, 50, 62, 93, 56, 57, 75 range standard deviation variance
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.10 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). Click the icon to view the data In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. H9: Ha =0 H1: Ha 0
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The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation of the population data set. 2, 7, 15, 5, 14, 10, 12, 8, 3, 9 The range is 1313. (Simplify your answer.) The population mean is . (Simplify your answer. Round to the nearest tenth as needed.) The population variance is nothing. (Simplify your answer. Round to the nearest tenth as needed.) The population standard deviation is nothing. (Simplify your answer. Round to the nearest tenth as needed.)
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
English Philippines) e to search Given Samples A and B below, Sample A: Sample B: Sample A: - 3.2 4.6 Sample B: - a. Calculate the mean and standard deviation for each sample. 2.1 2.6 Sample B: CV- 0.00 0.00 4.5 4.5 2.0 3.2 3.6 2.8 SA 0.00 96 50 11 b. Calculate the coefficient of variation for each sample. Sample A: CV. - 0.00 % E Round to two decimal places if necessari c. Which sample is more variable? 0.00 0.00 2.6 3.1 Sample A Sample B Neither sample is more variable than the other 3.8 4.1 3.8 4.9 3.5 4.6 land I
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 57.4 degrees. The mean of the frequency distribution is (Round to the nearest tenth as needed.)
Use the dataset below to fill in the blanks. The space between the data and the blanks isprovided so that you can show each data value's deviation and each data value's deviation squared.Sixteen families were selected at random and the number of children in each was recorded 0 0 0 1 1 2 2 2 2 2 3 3 4 6 8 12

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