Lisa lives 2050 feet due west of a park bench and Sarah lives 1620 feet due east of the same bench. Sarah left her house at 7:00 pm and traveled at a constant speed of 295 feet per minute towards the bench. Lisa left her house at the same time and traveled at a constant speed of 315 feet per minute towards the bench. Which of the following functions gives the distance d in feet between Lisa and Sarah in terms of the number t of minutes since 7:00 pm? O d = f(t) = 2050 – 295t d = f(t) = 1620 – 315t d = f(t) = 3670 – 610t

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Lisa lives 2050 feet due west of a park bench and Sarah lives 1620 feet due east of the same
bench. Sarah left her house at 7:00 pm and traveled at a constant speed of 295 feet per
minute towards the bench. Lisa left her house at the same time and traveled at a constant
speed of 315 feet per minute towards the bench. Which of the following functions gives the
distance d in feet between Lisa and Sarah in terms of the number t of minutes since 7:00 pm?
d = f(t) = 2050 – 295t
d = f(t) = 1620 – 315t
d = f(t) = 3670 – 610t
d = f(t) = 430t – 206
d = f(t) = 3670 + 610t
Transcribed Image Text:Lisa lives 2050 feet due west of a park bench and Sarah lives 1620 feet due east of the same bench. Sarah left her house at 7:00 pm and traveled at a constant speed of 295 feet per minute towards the bench. Lisa left her house at the same time and traveled at a constant speed of 315 feet per minute towards the bench. Which of the following functions gives the distance d in feet between Lisa and Sarah in terms of the number t of minutes since 7:00 pm? d = f(t) = 2050 – 295t d = f(t) = 1620 – 315t d = f(t) = 3670 – 610t d = f(t) = 430t – 206 d = f(t) = 3670 + 610t
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