v13.46.8.6.10Liquid hexane (CH3(CH,) CH;) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO,) and gaseous water (H,0). If 0.995 g of(0,)4water is produced from the reaction of 0.86 g of hexane and 4.6 g of oxygen gas, calculate the percent yield of water.Be sure your answer has the correct number of significant digits in it.%SubrSave For LaterCheck2020 McGraw-Hill Education. All Rights Reserved. Terms of Use PriMacBook Air002. v 16.78.6.10Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H,0).Suppose 61. g of hydrobromic acid is mixed with 57.3 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by thechemical reaction. Be sure your answer has the correct number of significant digits.x10Save For LaterSubmitCheckO 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use PrivaMacBook Air004)3.2.

Since you have posted multiple questions, we will solve first question for you. If you want any specific question to be solved then please specify the question or post only that question. Combustion is a reaction in which addition of oxygen takes place. On the combustion of hydrocarbons, carbon dioxide and water are formed. On the combustion of hexane, carbon dioxide and water are formed. Write the complete reaction of combustion. 2C6H14+19O2→12CO2+14H2O The number of moles of hexane is less than oxygen gas. So, it is the limiting reagent. Mass of hexane is 0.86 g. Molar mass of hexane is 86 g/mol. Calculate the number of moles of hexane. nC6H14=0.86 g86 g/mol=0.01 mol So, the number of moles of hexane are 0.01 mol. 2 moles of hexane reacts with oxygen to form 14 moles of water. Calculate the number of moles of water formed from 0.01 mol of hexane. nH2O=14 mol2 mol×0.01 mol=0.07 mol So, number of moles of water are 0.07 mol. Molar mass of water is 18 g/mol. Calculate the mass of water. Mass of water=18 g/mol×0.07 mol=1.26 g Therefore, theoretical yield of water is 1.26 g.Actual yield of water is 0.995 g. Percent yield of water is equal to the theoretical yield of water divided by its actual yield multiplied by 100. Calculate percent yield of water. Percent yield of water=0.995 g1.26 g×100=78.9% Therefore, percent yield of water is 78.9%.

Science

Chemistry

Liquid hexane (CH(CH. reacts with gaseous oxygen gas (0, to produce gaseous carbon dioxide (CO, and gaseous water (H,0). If 0.995 g of 4. water is produced from the reaction of 0.86 g of hexane and 4.6g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Liquid hexane (CH(CH. reacts with gaseous oxygen gas (0, to produce gaseous carbon dioxide (CO, and gaseous water (H,0). If 0.995 g of 4. water is produced from the reaction of 0.86 g of hexane and 4.6g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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