Liquid flowing at high speed in a wide, horizontal open channel under some conditions can undergo a hydraulic jump, as shown. For a suitably chosen control volume, the flows entering and leaving the jump may be considered uniform with hydrostatic pressure distributions. Consider a channel of width w, with water flow at D₁: = 0.6 m and V₁ 5.5 m/s. a.) Derive the formula for the depth downstream (D₂) as a function of the upstream parameters, D₁ and V₁. b.) Determine the depth (D₂) and velocity (V₂) in the subcritical regime of flow. = D₁ = 0.6 m 5 ms Hydraulic Jump D₂
Liquid flowing at high speed in a wide, horizontal open channel under some conditions can undergo a hydraulic jump, as shown. For a suitably chosen control volume, the flows entering and leaving the jump may be considered uniform with hydrostatic pressure distributions. Consider a channel of width w, with water flow at D₁: = 0.6 m and V₁ 5.5 m/s. a.) Derive the formula for the depth downstream (D₂) as a function of the upstream parameters, D₁ and V₁. b.) Determine the depth (D₂) and velocity (V₂) in the subcritical regime of flow. = D₁ = 0.6 m 5 ms Hydraulic Jump D₂
Chapter2: Loads On Structures
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Write the solutions legibly and correctly. Answer in 3 decimal places.
HYDRAULICS/FLUID
Transcribed Image Text:Liquid flowing at high speed in a wide, horizontal open channel under some conditions
can undergo a hydraulic jump, as shown. For a suitably chosen control volume, the flows
entering and leaving the jump may be considered uniform with hydrostatic pressure
distributions.
Consider a channel of width w, with water flow at D₁
=
pred
0.6 m and V₁
5.5 m/s.
a.) Derive the formula for the depth downstream (D₂) as a function of the upstream
parameters, D₁ and V₁.
b.) Determine the depth (D₂) and velocity (V₂) in the subcritical regime of flow.
D₁ = 0.6 m
V-5ms
Hydraulic Jump
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