Links (1) and (2) support rigid bar ABCD shown in the figure. Link (1) is bronze [E = 15,200 ksi] with a cross-sectional area of A1 = 0.545 in.? and a length of L1 = 16 in. Link (2) is cold-rolled steel [E = 30,000 ksi] with a cross-sectional area of A2 = 0.400 in.? and a length of L2 = 35 in. Use dimensions of a = 13.75 in., b = 15.75 in., and c = 20.00 in. For an applied load of P = 8 kips, determine: (a) the normal stresses in links (1) and (2). (b) the deflection of end Dof the rigid bar. D P. (1) L2 b B (2) a A X,u

Structural Analysis
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Chapter2: Loads On Structures
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Links (1) and (2) support rigid bar ABCD shown in the figure. Link (1) is bronze [E = 15,200 ksi]with a cross-sectional area of
A1 = 0.545 in.? and a length of L1 = 16 in. Link (2) is cold-rolled steel [E = 30,000 ksi] with a cross-sectional area of A2 = 0.400
in.? and a length of L2 = 35 in. Use dimensions of a = 13.75 in., b = 15.75 in., and c = 20.00 in. For an applied load of P = 8
kips, determine:
(a) the normal stresses in links (1) and (2).
(b) the deflection of end D of the rigid bar.
D
(1)
L2
b
a
A
X,u
Transcribed Image Text:Links (1) and (2) support rigid bar ABCD shown in the figure. Link (1) is bronze [E = 15,200 ksi]with a cross-sectional area of A1 = 0.545 in.? and a length of L1 = 16 in. Link (2) is cold-rolled steel [E = 30,000 ksi] with a cross-sectional area of A2 = 0.400 in.? and a length of L2 = 35 in. Use dimensions of a = 13.75 in., b = 15.75 in., and c = 20.00 in. For an applied load of P = 8 kips, determine: (a) the normal stresses in links (1) and (2). (b) the deflection of end D of the rigid bar. D (1) L2 b a A X,u
Find the internal forces F1 and F2 in links (1) and (2), respectively. Use the sign convention for internal axial forces.
F1 =
i
kips
F2 =
i
kips
Determine the normal stresses in links (1) and (2). Based on the sign conventions, a tensile normal stress is positive and a
compressive normal stress is negative. Use the sign convention for normal stresses discussed in Section 1.2.
01 =
21.53
ksi
02 =
! ksi
i
Determine the deflection of link (1). Use the sign convention for axial deformation.
d1 =
i
in.
Determine the deflection of end D of the rigid bar. Enter a positive value if it deflects to the right, or a negative value if it deflects
to the left.
Up =
in.
Transcribed Image Text:Find the internal forces F1 and F2 in links (1) and (2), respectively. Use the sign convention for internal axial forces. F1 = i kips F2 = i kips Determine the normal stresses in links (1) and (2). Based on the sign conventions, a tensile normal stress is positive and a compressive normal stress is negative. Use the sign convention for normal stresses discussed in Section 1.2. 01 = 21.53 ksi 02 = ! ksi i Determine the deflection of link (1). Use the sign convention for axial deformation. d1 = i in. Determine the deflection of end D of the rigid bar. Enter a positive value if it deflects to the right, or a negative value if it deflects to the left. Up = in.
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